Replace specified text from index to another index in array python

Question

I want to replace a searched text in an array from a specified element to another specified element in this array. I know there is a “replace” function but it will replace all the occurrences of that searched field. So I want to know if there is another function or another trick that can do what I want Like this:

myarray = ["time (1)",
"the text to replace ",
"time (2)",
"the text to replace ",
"time (3)",
"the text to replace ",
"time (4)",
"the text to replace ",
"time (5)",
"the text to replace ",
"time (6)",
"the text to replace ",
"time (7)",
"the text to replace ",
"time (8)",
"the text to replace ",
"time (9)",
"the text to replace ",
"time (10)",
"the text to replace "]

myfunc(4,8)

def myfunc(fromtime, totime):
    for line in myarray
    #find the time from (fromtime) to (totime) and replace 'text' with 'string' for example
    print myarray

Can any one help me? Please! Thank you!

What do you want to replace it to? can you give us your desired output? — static const
– static const, Commented Jun 20, 2019 at 16:02
Please provide a minimal reproducible example with what you've tried and your desired output. Are the elements in your list (note that this is a list, not an array) actually the word "time", or are they actual timestamps? — G. Anderson
– G. Anderson, Commented Jun 20, 2019 at 16:03
@G.Anderson no time is just a string that has to be before the number in my array that I want to look for so I can apply my function — it4Astuces
– it4Astuces, Commented Jun 21, 2019 at 8:36

Sebastien D · Accepted Answer · 2019-06-20 16:20:10Z

3

You could look for indexes of time (4) and time(8) but using the myarray.index() from there make the changes in the strings included into those limits

myarray = ["time (1)","the text to replace ","time (2)","the text to replace ","time (3)","the text to replace ","time (4)","the text to replace ","time (5)","the text to replace ","time (6)","the text to replace ","time (7)","the text to replace ","time (8)","the text to replace ","time (9)","the text to replace ","time (10)","the text to replace "] 

def myfunc(myarray, fromtime, totime):
    original_string , replace_string = 'text', 'string'
    start_index = myarray.index("time ({})".format(fromtime))
    end_index = myarray.index("time ({})".format(totime)) + 2 # + 2 because you want to also change value for the outbound limit
    myarray[start_index : end_index] = [value if idx%2 == 0 else value.replace(original_string, replace_string) for idx, value in enumerate(myarray[start_index : end_index]) ]
    return myarray

myfunc(myarray, 4,8)

Output

['time (1)',
 'the text to replace ',
 'time (2)',
 'the text to replace ',
 'time (3)',
 'the text to replace ',
 'time (4)',
 'the string to replace ',
 'time (5)',
 'the string to replace ',
 'time (6)',
 'the string to replace ',
 'time (7)',
 'the string to replace ',
 'time (8)',
 'the string to replace ',
 'time (9)',
 'the text to replace ',
 'time (10)',
 'the text to replace ']

answered Jun 20, 2019 at 16:20

Sebastien D

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1 Comment

it4Astuces Over a year ago

Can you join me here: chat.stackoverflow.com/rooms/195177/maya

Charles Dupont · Accepted Answer · 2019-06-20 16:12:29Z

2

Assuming that myarray has the given format, you could write something like:

def myfunc (fromtime, totime):
    i = fromtime*2 - 1
    while i <= (totime*2 - 1):
        myarray[i] = myarray[i].replace('text', 'string')
        i+=2

Output of myfunc(4, 8) is:

['time (1)',
 'the text to replace ',
 'time (2)',
 'the text to replace ',
 'time (3)',
 'the text to replace ',
 'time (4)',
 'the string to replace ',
 'time (5)',
 'the string to replace ',
 'time (6)',
 'the string to replace ',
 'time (7)',
 'the string to replace ',
 'time (8)',
 'the string to replace ',
 'time (9)',
 'the text to replace ',
 'time (10)',
 'the text to replace ']

Is this what you are after?

answered Jun 20, 2019 at 16:12

Charles Dupont

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