I have Array in this format.
rowData[0] = addRow(aa);
rowData[1] = addRow(aaa);
rowData[2] = addRow(aa);
rowData[3] = addRow(aa);
addRow is a function which gets this value process.But i don't want to give the Array Index, instead i want to give rowData[i], then put in a loop and access the elements.
rowData holds the an object which addRow returns.
var data = [rowData];
var table = Ti.UI.createTableView({
data:data
});
Use the Array.push function to store the data:
rowData.push(addRow(aa));
rowData.push(addRow(aaa));
.
.
.
.
.
Another alternative is:
rowData[rowData.length] = addRow(aa);
rowData[rowData.length] = addRow(aaa);
.
.
.
.
.
Use the regular index based iterations to get the data:
for(var i=0; i< rowData.length; i++){
var curItem = rowData[i];
}
for (var i = 0; i < rowData.length; i++)
{
rowData[i] = addRow(aa);
}
addRow(aa) and addRow(aaa) and how that relates to the array index...did u mean this?
var rowData = {};
rowData[aa] = addRow(aa);
rowData[aaa] = addRow(aaa);
for loop access
for(var index in rowData){
var data = rowData[index]
...
}
A loop may not be feasible in your case. This may be an idea: you can rewrite the Array.push prototype method:
Array.prototype._push = Array.prototype.push;
Array.prototype.push = function(val){ this._push(val); return this;};
After which you can chain the push operations:
rowData.push(addRow(aa))
.push(addRow(aaa))
.push(addRow(aa))
.push(addRow(aa));
But actually, it looks like you are mixing arrays with objects. Here's an answer I formulated earlier on that subject.
