Self executing lambda expression in Common Lisp

Question

I thought that this is the only way to write self executing lambda expression in Common LISP:

(funcall #'(lambda (x) (format t "~S" x)) 10)

but it seems that this also work in CLISP on GNU/Linux:

((lambda (x) (format t "~S" x)) 10)

which is more like you do this in Scheme. Is this something that is correct according to Common LISP spec? Does other CL implementation also work this way.

The lambda expressions here are not self executing. The question is more about applying lambda expressions to arguments. You can also go with (#'(lambda ...) argument) — Xero Smith
– Xero Smith, Commented Jun 3, 2019 at 21:41
@XeroSmith you're right it should be called immediately invoked lambda expression like in IIFE in JavaScript (that also were called self in the years ago before they change the name). — jcubic
– jcubic, Commented Jun 4, 2019 at 6:45

Rainer Joswig · Accepted Answer · 2019-06-01 11:11:07Z

6

That's standard Common Lisp syntax.

See lambda forms in Conses as Forms.

answered Jun 1, 2019 at 11:11

Rainer Joswig

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4 Comments

jcubic Over a year ago

Hyperspec if very confusing, I don't show any examples of stuff it explain.

Rainer Joswig Over a year ago

@jcubic if you look under LAMBDA, there is an example: lispworks.com/documentation/HyperSpec/Body/s_lambda.htm

Sylwester Over a year ago

While it is allowed to have lambda form in operator position it isn't very useful. At best it replaces a let.

Rainer Joswig Over a year ago

@Sylwester: the lambda form is for example used in macros, where it is sometimes less work to generate a LAMBDA form, than a LET form.

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