Possible Duplicates:
How to initialize an array to something in C without a loop?
How to initialize an array in C
How can I zero a known size of an array without using a for or any other loop ?
For example:
arr[20] = 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0;
This is the long way... I need it the short way.
int arr[20] = {0};
C99 [$6.7.8/21]
If there are fewer initializers in a brace-enclosed list than there are elements or members of an aggregate, or fewer characters in a string literal used to initialize an array of known size than there are elements in the array, the remainder of the aggregate shall be initialized implicitly the same as objects that have static storage duration.
int arr[20] = {}; without the 0?
float control[16] = {15.0}; is not an array with 15.0 copied 16 times, but is one 15.0, and the rest is 0.int arr[20];
memset(arr, 0, sizeof arr);
See the reference for memset
Note: You can use memset with any character.
Example:
int arr[20];
memset(arr, 'A', sizeof(arr));
Also could be partially filled
int arr[20];
memset(&arr[5], 0, 10);
But be carefull. It is not limited for the array size, you could easily cause severe damage to your program doing something like this:
int arr[20];
memset(arr, 0, 200);
It is going to work (under windows) and zero memory after your array. It might cause damage to other variables values.
Using memset:
int something[20];
memset(something, 0, 20 * sizeof(int));
int arr[20] = {0} would be easiest if it only needs to be done once.
man bzero
NAME
bzero - write zero-valued bytes
SYNOPSIS
#include <strings.h>
void bzero(void *s, size_t n);
DESCRIPTION
The bzero() function sets the first n bytes of the byte area starting
at s to zero (bytes containing '\0').
