Pulling Variable out of an Array

Question

I am trying to pull a variable out of an array with name of variable coming from another variable.

I have tried both: $get_results[$name] and $get_results->$name with no success.

I keep on getting following error on $get_results[$name]: Fatal error: Uncaught Error: Cannot use object of type stdClass as array in But on $get_results->$name it skips over it.

The $name is loaded by user. The $get_results is loaded by MYSQL database

$name = 'test2'
$get_results = array('test' - > '1', 'test2' - > '2');

if (!isset($get_results[$name])) {
  if (empty($get_results[$name])) {
    $value = $get_results[$name];
  } else {
    $value = "";
  }
}
elseif(!isset($_POST[$name])) {
  $value = Input::get($name);
} else {
  $value = "";
}

I am trying to get the value from $get_results from test2.

I have made the changes to my script:

    if(isset($get_results[$name])){
        if(!empty($get_results[$name])){
            $value = $get_results[$name];
        } else {
            $value = "";
        }
    }elseif(!isset($_POST[$name])){
        $value = Input::get($name);
    }else {
        $value = "";
    }

When I try to pull the data from $get_results[$name] its dies with error: Cannot use object of type stdClass as array

Faisal Rahman Avash · Accepted Answer · 2019-05-20 02:47:09Z

3

You are running into a syntax error while initializing your array. Associative array uses => rather than ->.

So, just replace

$get_results = array ('test' -> '1', 'test2' -> '2');

with

$get_results = array ('test' => '1', 'test2' => '2');

answered May 20, 2019 at 2:47

Faisal Rahman Avash

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Comments

PHP Geek · Accepted Answer · 2019-05-20 05:04:09Z

1

your get_results variable returns an object

use this:

get_results->$name;

answered May 20, 2019 at 5:04

PHP Geek

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1 Comment

user8776656 Over a year ago

It fixed the issue. Thank You

user3783243 · Accepted Answer · 2019-05-20 03:12:56Z

1

First thing you have a syntax error in array creation update -> to =>.

do

$name = 'test2';
$get_results = array ('test' => '1', 'test2' => '2');
echo 'value will be : '.$get_results[$name];die;

Output:

value will be : 2

Second you have logic error too in if Please check below corrected code

$name = 'test2';
$get_results = array('test' => '1', 'test2' => '2');
if (isset($get_results[$name])) {//check if $name is in array will true
    if (!empty($get_results[$name])) {//check if $name in array is not empty
        $value = $get_results[$name];
    } else {
        $value = "test 1";
    }
} elseif (!isset($_POST[$name])) {
    $value = "test 2";//Input::get($name);
} else {
    $value = "test 3";
}
echo 'value will be : '.$value;die;

Output:

value will be : 2

edited May 20, 2019 at 3:12

user3783243

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answered May 20, 2019 at 2:54

M.Hemant

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