I want to declare array of type integers named sequence.
After a simulation sequence it will look like [1,3,4,59.........n elements]. I do not know the value of n as it is a random integer.
How can I declare sequence as an array of type int? I did like sequence= [1,1] but this did not work out as sometimes only 1 element and then it has 2 instead of 1 element.
In cases where you cannot preallocate the array (when you don't know the size of the array in advance), you can use the following method:
sequence = [];
sequence(end+1) = 1;
sequence(end+1) = 3;
sequence(end+1) = 4;
...
Think of this method as treating sequence as a C++ std::vector and sequence(end+1) = 1 is equivalent to sequence.push_back(1).
The standard format for declaring an array is:
foo = [];
and you can set any element of the array, at any time, and Matlab will resize automatically. For example:
foo = [];
foo(4) = 1
yields
foo = [ 0 0 0 1]
If you don't know how many elements your array needs to hold, you can do as Jacob suggests and simply resize the array every time. However, if this causes bottlenecks in your code (which you can find by using the profile tool in Matlab), you may want to resize less often, and use a placeholder value for the as-yet-unused elements.
You may want to look into the linspace( from, to, numberOfElements ) function.
var=[ val1 val2 val3....valn]
for i=1:numel(var)
result=var(i)
end
foo=typecast (foo,'int16')to convert data type offoofromdouble(default) toint16type. Alternatively, declarefooas following:foo=int16 ([]). P.S. : You can choose from a variety of data types.