Move Files Specific Folder

Question

I need bash script, these are my files:

./2019-01-11_15-00-29_UTC.mp4
./2019-02-10_17-42-18_UTC.mp4
./2019-01-03_14-45-43_UTC.mp4
./2018-12-24_13-00-32_UTC.mp4
./2018-12-09_19-50-59_UTC.mp4
./2019-01-11_14-51-08_UTC.mp4
./2019-01-06_16-41-54_UTC.mp4
./2019-02-03_10-33-33_UTC.mp4
./2019-02-16_18-21-30_UTC.mp4

wanna make two folder 2018 & 2019 then move files own folder. I use this code:

ls *.mp4 | awk -F"-" '{print $1}' | while read day file ; do mkdir -p "$day"; mv "$file" "$day"; done

It makes folder but not move

Paul Hodges · Accepted Answer · 2019-04-24 15:05:51Z

Aren't you getting errors? When I run it I get

mv: cannot stat '': No such file or directory

once for each file. The reason is that file isn't being set in your loop.

ls *.mp4 | awk -F"-" '{print $1}'

Will generate a list of years

That's a single column of data.

while read day file

reads the year into day (day?) and since there's no more data, leaves file empty.

mkdir -p "$day"

works fine, but

mv "$file" "$day"

evaluates to

mv "" "2018"

Try this.

for f in *.mp4
do mkdir -p "${f%%-*}" && mv "$f" "${f%%-*}"
done

The ${f%%-*} just returns $f with everything from the first dash removed. The result:

$: find
.
./2018
./2018/2018-12-09_19-50-59_UTC.mp4
./2018/2018-12-24_13-00-32_UTC.mp4
./2019
./2019/2019-01-03_14-45-43_UTC.mp4
./2019/2019-01-06_16-41-54_UTC.mp4
./2019/2019-01-11_14-51-08_UTC.mp4
./2019/2019-01-11_15-00-29_UTC.mp4
./2019/2019-02-03_10-33-33_UTC.mp4
./2019/2019-02-10_17-42-18_UTC.mp4
./2019/2019-02-16_18-21-30_UTC.mp4

BlackPearl · Accepted Answer · 2019-04-25 13:45:10Z

1

You can use xargs to achieve this.

ls *.mp4 | xargs -I{} sh -c 'folder=`echo {} | cut -d"-" -f1`;mkdir -p $folder;mv {} $folder/'

Here, the entire file names are sent to xargs and, for each file the folder name is obtained using the cut command. Then the file is moved into the created folder.

More about xargs: http://man7.org/linux/man-pages/man1/xargs.1.html

Edited

for file in *.mp4 ; do
    date=$(echo $file | cut -d'_' -f1)
    year=$(echo $date | cut -d'-' -f1)
    month=$(echo $date | cut -d'-' -f2)
    day=$(echo $date | cut -d'-' -f3)
    mkdir -p $year/$month/$day
    mv $file $year/$month/$day/
done

edited Apr 25, 2019 at 13:45

answered Apr 24, 2019 at 14:36

BlackPearl

1,6721 gold badge10 silver badges16 bronze badges

9 Comments

jali316 Over a year ago

Is it posible cd to $folder at the end.

BlackPearl Over a year ago

You can do anything which you might do on a normal shell script.

jali316 Over a year ago

I add && cd $folder ; ls *.mp4 | xargs -I{} sh -c 'folder=echo {} | cut -d"-" -f2;mkdir -p $folder;mv {} $folder/' but not work.

BlackPearl Over a year ago

I don't understand what cd is going to do in this case. What are you trying to achieve?

jali316 Over a year ago

after cuting with first part of name I want to cut second part of name ,first part is year second part is month 2019-01-03_14-45-43_UTC.mp4 as you know we should go to 2019 folder then run again for cuting cut -d"-" -f2

|

Collectives™ on Stack Overflow

Move Files Specific Folder

2 Answers 2

Comments

9 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

9 Comments

Your Answer

Sign up or log in

Post as a guest

Related