cell array initialize

Question

i have a cell array with elements 22*22,18*18*6,14*14*6,10*10*6,6*6*6.can u please help me to initialize it

Update:

s{l(:,:,feature_map)=zeros(22,22),zeros(18,18,6),zeros(14,14,6),zeros(10,10,6),zeros(6*6*6)

By using the above command first element of cell array is empty.all other elements have 22*22*6 elements.it'l create problems in convolution

code is:

num_of_maps_in_layer{1}=1;
for i=1:3
    num_of_maps_in_layer{i+1}=6; 
end
num_of_maps_in_layer{5}=6; 

for l=2:5
    for feature_map=1:num_of_maps_in_layer{l}
        sensitivity{l}(:,:,feature_map)=zeros(22,22),zeros(18,18,6),zeros(14,14,6),zeros(10,10,6),zeros(6*6*6)
    end
end

@user689593: Please read through some of these resources: How to ask a smart question?, Style guide for questions and answers, How To Ask Questions The Smart Way — gnovice
– gnovice, Commented Apr 5, 2011 at 15:44
In your example, what is l? What is feature_map? What do you want s and its contents to look like (i.e. size, number of dimensions, etc.)? These are the details we need from you, otherwise we're just making blind stabs in the dark. — gnovice
– gnovice, Commented Apr 5, 2011 at 16:06
@user689593: When you make considerable modifications to your question, please do it such way that it's obvious related to earlier answers. Thanks — eat
– eat, Commented Apr 5, 2011 at 17:12

gnovice · Accepted Answer · 2011-04-05 16:22:40Z

2

I think this is what you want to do:

sensitivity = {zeros(22,22),...
               zeros(18,18,6),...
               zeros(14,14,6),...
               zeros(10,10,6),...
               zeros(6,6,6)};

This creates a 5-element cell array sensitivity. The first cell contains a 22-by-22 numeric array of zeroes, the second cell contains an 18-by-18-by-6 numeric array of zeroes, etc.

answered Apr 5, 2011 at 16:22

gnovice

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Comments

aioobe · Accepted Answer · 2011-04-05 15:18:53Z

1

Not sure what you want to initialize the matrices with, but if you just want do declare them and don't really care what they contain, you could do

ones(22, 22)
ones(18,18,6)
ones(14,14,6)
...

or you could use zeros function for 0-filled matrices.

answered Apr 5, 2011 at 15:18

aioobe

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1 Comment

user1234 Over a year ago

s{l}(:,:,feature_map)=zeros(22,22),zeros(18,18,6),zeros(14,14,6),zeros(10,10,6),zeros(6*6*6). by using the above command first element of cell array is empty.all other elements have 22*22*6 elements.it'l create problems in convolution.please help

eat · Accepted Answer · 2011-04-05 15:19:58Z

1

By any change did you meant by initialization something like this:

1> ca= {22* 22, 18* 18* 6, 14* 14* 6, 10* 10* 6, 6* 6* 6}
ca =
{
  [1,1] =  484
  [1,2] =  1944
  [1,3] =  1176
  [1,4] =  600
  [1,5] =  216
}

answered Apr 5, 2011 at 15:19

eat

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1 Comment

user1234 Over a year ago

sensitivity{l}(:,:,feature_map)=zeros(22,22),zeros(18,18,6),zeros(14,14,6),zeros(10,10,6),zeros(6*6*6). can u please correct this?first element of cell array is empty.all other elements have 22*22*6 elements.it'l create problems in convolution.please help

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