Invalid argument error while decoding a JSON file in php

Question

I am trying to decode a JSON file using PHP. This is the Code that I am using.

<?php
  $content =  file_get_contents('result.json');

  $contendecoded = json_decode($content);

  print_r($contendecoded);

  foreach ($contendecoded as $each) {
    # code...
    echo '<li>' .$each->Receiver. '</li>';
  }
  ?>

This is the result.json file

{"Sender":"254705537065","Receiver":"7528452889","Amount":"1","FName":"Martinique","AccessToken":"8XRTHN59NCHvUGAASGbK6IcCzYcn"},
{"Sender":"254705537065","Receiver":"6584238686","Amount":"2","FName":"Phillipines2","AccessToken":"O4wBFWPmFA8ayKGYahhpdCAW97mg"},
{"Sender":"254705537065","Receiver":"6584238686","Amount":"2","FName":"Phillipines2","AccessToken":"O4wBFWPmFA8ayKGYahhpdCAW97mg"},
{"Sender":"254705537065","Receiver":"6584238686","Amount":"36","FName":"Phillipines3","AccessToken":"O4wBFWPmFA8ayKGYahhpdCAW97mg"},
{"Sender":"254705537065","Receiver":"6584238686","Amount":"36","FName":"Phillipines3","AccessToken":"O4wBFWPmFA8ayKGYahhpdCAW97mg"}

I am getting this error

Warning: Invalid argument supplied for foreach() in C:\xampp\htdocs\website\receive.php on line 8

The line 8 refereed by the error is

foreach ($contendecoded as $each) {

How do I solve this?

you json not in array format like [{},{}], try with '$contendecoded = array(json_decode($content))' — Ashu
– Ashu, Commented Mar 18, 2019 at 4:05

shawn · Accepted Answer · 2019-03-18 04:01:45Z

1

Your content of the file is NOT valid JSON.

You can refer this question (also answered by me) Decoding multiple JSON objects in PHP

function json_decode_multi($s, $assoc = false, $depth = 512, $options = 0) {
    if(substr($s, -1) == ',')
        $s = substr($s, 0, -1);
    return json_decode("[$s]", $assoc, $depth, $options);
}

$content =  file_get_contents('result.json');
$contendecoded = json_decode_multi($content);
print_r($contendecoded);

answered Mar 18, 2019 at 4:01

shawn

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1 Comment

Martin Mbae Over a year ago

Your answer is working even without editing the JSON. Kudos.

Murzid · Accepted Answer · 2019-03-18 03:59:06Z

1

Please post again your PHP code
JSON code not valid (need bracket / parenthesis)

answered Mar 18, 2019 at 3:59

Murzid

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1 Comment

Martin Mbae Over a year ago

You saved my day. I am following a tutorial and I somehow forgot to add [] brackets over my JSONfile. It's now working. Thank you.

Suraj Kumar · Accepted Answer · 2019-03-18 04:46:14Z

1

I think you need a bracket pair in the JSON file, like this

[
{},
{}
]

edited Mar 18, 2019 at 4:46

Suraj Kumar

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answered Mar 18, 2019 at 4:04

Pan Ke

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