Issue with php form: button input not triggering if statement

Question

As stated above, when I try to send a form using php my if statement is not being triggered and the variable is not being set to my desired value.

Relevant PHP:

if($_SERVER["REQUEST_METHOD"] == "POST"){


    if(isset($_POST['time_pickedm']) == "9:00"){
            $timepicked = "09:00:00";   

        } 
    }

Relevant HTML:

<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="POST">
<input type="button" class="<?php echo $buttoncolour ?>" name= 'time_pickedm' value = "9:00">
<input type="submit" class="btn btn-primary" name="Submit">
</form>

Any help would be appreciated

Renzo Ezagui · Accepted Answer · 2019-03-16 16:26:18Z

1

Your condition is wrong, try:

 if($_SERVER["REQUEST_METHOD"] == "POST"){


        if(isset($_POST['time_pickedm']) && $_POST['time_pickedm']== "9:00"){
            $timepicked = "09:00:00";

        }
    }

EDIT: I think i found it!

in your html you have 2 buttons, so the time_pickedm is not going to your php. try replacing button for text:

<input type="text" class="<?php echo $buttoncolour ?>" name= 'time_pickedm'     value = "9:00">

edited Mar 16, 2019 at 16:26

answered Mar 16, 2019 at 15:36

Renzo Ezagui

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11 Comments

George Smith Over a year ago

I've tried this but the if statement still doesn't get called

Renzo Ezagui Over a year ago

@GeorgeSmith can you echo $_POST['time_pickedm'] or var_dump the $_POST before the if?.

George Smith Over a year ago

echo $_POST['time_pickedm'] before the if produced an undefined index error

Renzo Ezagui Over a year ago

@GeorgeSmith and thats why your if is not returning true. Did you var_dump the $_POST, so you can check?

George Smith Over a year ago

var_dump produces: array(0) { }

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prasanth · Accepted Answer · 2019-03-16 15:33:04Z

0

You if condition invalid .If time_pickedm is present in array is always true .

its just like if(true == "9:00")

So Change to separate validate the condition

if(isset($_POST['time_pickedm']) && $_POST['time_pickedm'] == "9:00")

edited Mar 16, 2019 at 15:33

answered Mar 16, 2019 at 15:28

prasanth

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11 Comments

Qirel Over a year ago

The $a variable in this answer should be replaced by $_POST.

prasanth Over a year ago

could you evaporate what is not working.And what is problem ?

George Smith Over a year ago

when I try that, if($_SERVER["REQUEST_METHOD"] == "POST"){ gets called but the if statement doesn't, and my variable doesn't get set to 9:00 and just stays as false

prasanth Over a year ago

simply check print_r($_POST);exit(); on top of the first line code.See the param is shown or not

George Smith Over a year ago

that produces "Array()"

|

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