function gets function as an argument and throws 'numpy.ndarray' object is not callable

Question

I call a function with other function as an argument. The other function return numpy.ndarray.

The code:

class CLASS:
    def method1(self):
        size = 10
        return np.zeros([size,size])
    def method2(self, method):
        res = method()

a = CLASS ()
b = a.method2(a.method1())

The first function throws me TypeError: 'numpy.ndarray' object is not callable

I want to run method2() in the cycle giving different functions as an argument.

QUESTION: Is it any way to run that in Python 3?

I have trouble understanding your question. Consider reformatting it with an edit. — leonheess
– leonheess, Commented Mar 13, 2019 at 15:05

Monkeyanator · Accepted Answer · 2019-03-13 15:08:09Z

1

It seems like you are passing the result of calling method1 (which is in fact a numpy.ndarray) into method2 rather than the method itself.

The call at the end should be a.method2(a.method1) without the parens.

edited Mar 13, 2019 at 15:08

answered Mar 13, 2019 at 15:00

Monkeyanator

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Comments

Wolph · Accepted Answer · 2019-03-13 15:00:40Z

0

The a.method1() returns the result of np.zeros(...) which is a numpy.ndarray

So When you're trying to call method() in method2() it fails because that's not a function.

You probably want this instead:

import numpy as np

class CLASS:
    def method1(self):
        size = 10
        return np.zeros([size,size])
    def method2(self, glcm):
        pass

a = CLASS ()
b = a.method2(a.method1())

answered Mar 13, 2019 at 15:00

Wolph

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