How can i reduce this condition ?
item is always a string
for item in list_of_items:
if ('beans' in item or 'apple' in item or 'eggs' in item or 'banana' in item) and ('elephant' not in item) or 'chicken' not in item:
print(item)
I mean can I somehow give list of words to check every possibility?
You can use any with a generator or list comprehension:
if any(word in item for word in ['apple', 'beans', 'eggs', 'banana', 'elephant', 'chicken')):
]You can use any for the first part.
However the second part cannot be reduced
if any(w in item for w in ('beans', 'apple', 'eggs', 'banana')) and ('elephant' not in item) or 'chicken' not in item:
Not useful for your case but you should be aware that all is also useful.
You can reduce this if 'a' not in item and 'b' not in item to if all(w not in item for w in ('a', 'b')
Using list-comprehension:
good_items = ['beans','apple','eggs','banana', 'elephant', 'chicken']
list_of_items = ['apple', 'grapes', 'elephant', 'chicken']
print([x for x in list_of_items if x in good_items and x not in ['elephant', 'chicken']])
OUTPUT:
['apple']
('elephant' not in item) or 'chicken' not in item not ('elephant' not in item or 'chicken' not in item)
set(list_of_items).intersection({'beans', 'apple', 'eggs', 'banana'})