Dynamically call php object property

Question

In the php 7 docs, there's http://php.net/manual/en/migration70.incompatible.php#migration70.incompatible.variable-handling.indirect. I'm trying to use this to call property dynamically. This code only prints v1. I want it to print v1pqrxyz

How can I do that? I'm using PHP version 7.0


class test{

    public $v1 = "v1";

    public function f1($a){
        return $a;
    }

    public function f2($b){
        return $b;
    }
}

$test1 = new test();

$arr = ['v1', 'f1("pqr")', 'f2("xyz")'];

foreach ($arr as $value) {
    echo $test1->{$value};
}

You would need eval or regular expressions to handle string expressions like 'f1("pqr")'. Both are unsafe and/or error prone. You should not do it. Whenever possible use ['v1', ['f1', ['arg1', 'arg2']], 'v2'] instead. — Pinke Helga
– Pinke Helga, Commented Feb 26, 2019 at 19:25

Nicolas Heimann · Accepted Answer · 2019-02-26 19:35:11Z

2

It is not possible the way you constructed it, even if it looks promising. But, you could do the following for methods

$arr = [
   ['f1', ['pqr']],
   ['f2', ['xyz']],
   # or some multi argument function
   #['f3', ['a', 'b']],
];

foreach ($arr as $value) {
    list($method, $args) = $value;
    echo $test1->$method(...$args);
}

and members could be accessed like this

$arr = [
   'v1'
];

foreach ($arr as $member) {
    echo $test1->$member;
}

edited Feb 26, 2019 at 19:35

answered Feb 26, 2019 at 19:17

Nicolas Heimann

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Comments

tokkerbaz · Accepted Answer · 2019-02-26 19:17:04Z

0

Try to use call_user_func()

 foreach ($arr as $value) {
   echo call_user_func([$test1,$value]);
 }

answered Feb 26, 2019 at 19:17

tokkerbaz

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1 Comment

Amitoz Deol Over a year ago

I'm getting error when doing it this way Warning: call_user_func() expects parameter 1 to be a valid callback, class 'test' does not have a method 'f1()'

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