I had a quick question. Is there a way to force the standard namespace to have the std:: scope qualifier? Something like abs and what not; all std functions have to have their scope defined.
I'm not using namespace std anywhere nor am I using std::abs or something like that. It might be important to say I have Windows.h included, which I feel may be where some of these unscoped functions are originating from.
The standard does not forbid other namespaces to have functions that are named abs just because there are functions named abs in std namespace. That's true of all other functions defined in the std namespace.
If you want to be certain that you use std::abs. and not any other version of abs, then by all means, use std::abs. Then, it's immaterial whether there are other versions of abs defined in the windows.h header file.
Calling abs instead of std::abs you are simply using abs from C
The rule in C++ is that #include <cmath> puts the declaration of abs in the namespace std and is allowed to also put the declaration of abs in the global namespace.
Another rule in C++ is that #include <math.h> puts the declaration of abs int he global namespace and is allowed to also put the declaration of abs in the namespace std.
So, no, you can't assume that #include <cmath> won't put abs into the global namespace.
The reason for this rule instead of the "obvious" one that #include <cmath> puts names only in std is that the latter rule can be nasty to implement if the C++ implementors don't also have control over the C headers. In that case, the C++ headers would have to have duplicate declarations for all of the C functions, and any change to the C headers would have to be carried through into the C++ headers, which produces a logistical nightmare.
absetc) which is whystdis not required, butstd::absdoes exist so you can still qualify it