The following two ifs produced different results(first if echos hi, second does not), why? why didn't the variable assignment on $t work? is this due to $t's local scope inside the if conditional?
if(isset($_REQUEST["test"]) && $t=trim($_REQUEST["test"]) && !empty($t)){
echo 'hi'
}
if(isset($_REQUEST["test"]) && $t=trim($_REQUEST["test"])){
if(!empty($t))echo 'hi'
}
&& has a higher precedence than =, hence the first expression is evaluated as:
isset($_REQUEST['test']) && $t = (trim($_REQUEST['test']) && !empty($t))
Since !empty($t) is evaluated before anything is assigned to $t, the expression is false. You could fix this by explicitly setting parentheses, or by using a less awkward way to write it:
if (isset($_REQUEST['test']) && trim($_REQUEST['test'])) {
echo 'hi';
}
trim($_REQUEST['test']) will evaluate to true or false just by itself, no empty necessary. If you actually need the trimmed value later, you can save it like so:
if (isset($_REQUEST['test']) && ($t = trim($_REQUEST['test']))) {
echo 'hi';
}
If you make minor modification like this in your code:
if(isset($_REQUEST["test"]) && ($t=trim($_REQUEST["test"])) && !empty($t)){
echo '1: hi<br/>';
}
if(isset($_REQUEST["test"]) && $t=trim($_REQUEST["test"])){
if(!empty($t))
echo '2: hi<br/>';
}
Then both 1: hi and 2: hi will be printed. Difference is parenthesis around first $t assignment.
