I'd like to replace occurrences of string with different values (from dictionary).
string = 'asfd @@@ fdsfd @@@ ffds @@@ asdf'
kv = {1: 'hi', 2: 'there', 3: 'bla'}
Expected:
string = 'asfd hi fdsfd there ffds bla asdf'
I've tried several solutions particularly with .replace or re.sub but still didn't find a good one.
A one-line solution:
string.replace('@@@', '{}', len(kv)).format(*kv.values())
Short explanation:
'@@@' strings with the python string formatting identifier '{}'. len(kv) reduces the number of replaces to the length of the dict, avoiding IndexError when the dict has less elements than the number of '@@@' in the stringkv.values()*kv.values() and pass this as argument to the string format method.Sample code execution:
Input
string = 'asfd @@@ fdsfd @@@ ffds @@@ asdf'
kv = {'1': 'hi', '2': 'there', '3': 'bla'}
And output
string.replace('@@@', '{}', len(kv)).format(*kv.values())
#Out: 'asfd hi fdsfd there ffds bla asdf'
Advantage of this solution:
No explicit looping (explicit looping is almost always a bad idea in python) and only one line of code. Furthermore this is also working when the number of '@@@' is less **or greater than the number of values in kv**, when the count parameter in str.replace is specified.
This leads to the final and 99% failsafe variant of my solution, using the len of the dict as count argument in replace:
string.replace('@@@', '{}', len(kv)).format(*kv.values())
@ this should be the accepted solution (+1).
This is one approach using str.replace with optional parameter count.
Ex:
s = 'asfd @@@ fdsfd @@@ ffds @@@ asdf'
kv = {'1': 'hi', '2': 'there', '3': 'bla'}
for k, v in sorted(kv.items()):
s = s.replace("@@@", v, 1)
print(s)
You can use re.sub to get the job done with out any sorting
Return the string obtained by replacing the leftmost non-overlapping occurrences of pattern in string by the replacement repl. If the pattern isn’t found, string is returned unchanged. repl can be a string or a function; if it is a string, any backslash escapes in it are processed.
import re
string = 'asfd @@@ fdsfd @@@ ffds @@@ asdf'
kv = {'1': 'hi', '2': 'there', '3': 'bla'}
class repl:
def __init__(self):
self.called=0
def __call__(self,match):
self.called+=1
return kv[str(self.called)]
print(re.sub('@@@',repl(),string))
OUTPUT
asfd hi fdsfd there ffds bla asdf
string = 'asfd @@@ fdsfd @@@ ffds @@@ asdf'
kv = {1: 'hi', 2: 'there', 3: 'bla'}
for k,v in kv.items():
string = string.replace('@@@', v, 1)
print(string)
OUTPUT:
asfd hi fdsfd there ffds bla asdf
kv = {'1': 'hi', '2': 'there', '3': 'bla'}
string = 'asfd @@@ fdsfd @@@ ffds @@@ asdf'
string_list=string.split('@@@')
string_list_out=[]
for i in range(len(string_list)):
if i==0:
string_list_out.append(string_list[0])
else:
string_list_out.append(kv[str(i)])
string_list_out.append(string_list[i])
string_list_out=''.join(string_list_out)
print(string_list_out)
'asfd hi fdsfd there ffds bla asdf'
