How to format a floating number to variable width in Python

Question

I am writing code where I would like the user to enter the desire decimal point precision. For example:

for x in numbers:
    print "{:10.*f}".format(x)

...except where the '*' is I would like to place a variable that which the user provided value. My search for a solution in available documentation has proved unfruitful.

gmds · Accepted Answer · 2019-02-05 05:32:39Z

1

How about print '{:10.{precision}f}'.format(x, precision=precision), where precision is a value defined elsewhere?

answered Feb 5, 2019 at 5:32

gmds

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2 Comments

CGregg Over a year ago

Thanks for your help. I was looking for a needle in a haystack. Was nice to have the needle come to me. Thanks again.

gmds Over a year ago

No problem. If I helped you, please accept my answer!

taurus05 · Accepted Answer · 2019-02-05 05:44:33Z

1

Python One-liner

number = 10.123456789
print ('{:10.{precision}f}'.format(number, precision=int(input("Enter the precision"))))

Output :   
>>> print ('{:10.{precision}f}'.format(number, precision=int(input("Enter the precision\n"))))
    Enter the precision
    5
      10.12346

edited Feb 5, 2019 at 5:44

answered Feb 5, 2019 at 5:36

taurus05

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