this function does not return the result, what could I be doing wrong?
<?php
function iisset($name){
return ${$name}; // "${$name}" does not work
}
$hola = 1;
echo iisset("hello");
Note: it works correctly if it is not in a function
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php.net/manual/en/language.variables.scope.phpuser1597430– user15974302019-01-28 02:33:45 +00:00Commented Jan 28, 2019 at 2:33
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1 Answer
You have a few issues going on here. The first is an issue of scope. Nothing outside the function iisset($name) is normally visible to it. Therefore any variable defined outside iisset($name) can't been seen.
So the first step would be to make it global
by adding global ${$name}; to the first line after the function declaration. The second would be that there is no variable named "hello" outside the function. If you are trying to access the $hola then I would recommend the following:
<?php
function iisset($name){
global ${$name};
return ${$name}; // "${$name}" does not work
}
$hola = 1;
echo iisset("hola");
1 Comment
LΞИIИ
Incredible, with the global the problem is solved, thank you very much