Eg. Map[Map[String,Int],Int] I need to convert it into Map[String,Int] i.e Int in value part of inner map is replaced with Int in value part of outer map.
For example:
val innerMap = Map("a"->1)
val outerMap = Map(innerMap, 2)
Required result:
resultMap = Map("a"->2)
Even though you haven't answered my question about duplicate String values, I'm going to guess that what you want is something like this.
val mmsii :Map[Map[String,Int],Int] =
Map(Map("a"->1)->11,Map("b"->2)->22)
mmsii.flatMap{case (m,v) => m.keys.map(_ -> v)}
Or, using the sometimes friendlier for comprehension:
for {
(m,v) <- mmsii
(k,_) <- m
} yield k->v
Keep in mind, if there are duplicate String keys then only one String->Int pair will be retained and the others will be lost.
Pretty much the same as @jwvh's solution, just a little more explicit
val nestedMap: Map[Map[String, Int], Int] = Map(
Map("k1" -> 1) -> 11,
Map("k2" -> 2, "k3" -> 3) -> 22
)
val unnestedMap: Map[String, Int] = nestedMap.flatMap { (outerTuple: (Map[String, Int], Int)) =>
val innerMap: Map[String, Int] = outerTuple._1
val commonVal: Int = outerTuple._2
innerMap.map { (innerTuple: (String, Int)) =>
(innerTuple._1 -> commonVal)
}
}
print(unnestedMap)
You can leverage this solution to your problem
val anotherMap = Map(Map("a" -> 1) -> 10, Map("b" -> 2) -> 11, Map("c" -> 3) -> 12)
anotherMap.flatMap {
case (keyMap, value) =>
keyMap map {
case (k, _) => Map(k -> value)
}
}
// res0: scala.collection.immutable.Iterable[scala.collection.immutable.Map[String,Int]] = List(Map(a -> 10), Map(b -> 11), Map(c -> 12))
Map(Map("a"->1)->11,Map("a"->2)->22)Should the result be"a"->11or"a"->22?Map(Map("a" -> 1, "b" -> 2) -> 3))?