How to get a end string using regex in python?

Question

I have some string which I already mentioned in previous question

s = "[1,12:12] call basic_while1() Error Code: 1046. No database selected"

s1="[1,12:12] call add() Asdfjgg Error Code: 1046. No database aa selected"

s2= "[1,12:12] call add()"

s3= "[1,12:12]"

s4="Error Code: 1046. No database selected"

s5="END: Error Code: 2134. database doen't exist"

regex=(?:^\[(\d+),(\s?[0-9:]+)\](?:\s+(.+?)\s?)?(?:Error Code:.*)?$)|(?:()()()(Error Code:.*$))

using that regex I get output like

['1', '12:12', 'call basic_while1()']
['1', '12:12', 'call add() Asdfjgg']
['1', '12:12', 'call add()']
['1', '12:12']
['', '', '', 'Error Code: 1046. No database selected']

now I want to make change in that regex only and get out put like

['', '', '','Error Code: 1046. No database selected']
['', '', '','Error Code: 1046. No database selected']
['', '', '']
['', '']
['Error Code: 1046. No database selected']

I modified this to

(?:^\?:[(\d+),(\s?[0-9:]+)\](?:\s+(.+?)\s?$)?(Error Code:.*))|(?:()()()(Error Code:.*$))

but it didn't work is it possible to get output like this using that Regex?

You can't have newlines in string literals unless you use triple quotes. — Barmar
– Barmar, Commented Dec 21, 2018 at 7:21
got it, and I recommend you to watch my last question @Barmar — user10754733
– user10754733, Commented Dec 21, 2018 at 7:23
Your question should be standalone. While linking toa previous question is fine as a reference, it should not be required to fully understand what you're asking. — Mad Physicist
– Mad Physicist, Commented Dec 21, 2018 at 7:26

The Pjot · Accepted Answer · 2018-12-21 07:43:06Z

1

Try with

regex='Error Code: \d+.*'
match = re.search(regex, s)
if match:
    print(match.group(0))
    # Output:
    # 'Error Code: 1046. No database selected'

edited Dec 21, 2018 at 7:43

The Pjot

1,8581 gold badge13 silver badges21 bronze badges

answered Dec 21, 2018 at 7:28

user2314737

29.7k20 gold badges109 silver badges126 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

user10754733 Over a year ago

it works , but if scenario like s2 and s3 , it gives me a error , I want to make only one regex for it

user10754733 Over a year ago

@ThePjot this sol is good , but I want to change in this regex=(?:^[(\d+),(\s?[0-9:]+)](?:\s+(.+?)\s?)?(?:Error Code:.*)?$)|(?:()()()(Error Code:.*$)) and want this kind of output .I don't want to make new regex , thanks

Jan · Accepted Answer · 2018-12-21 10:06:51Z

1

You could use

^
(?:\[(?P<d1>[\d,]+):(?P<d2>[\d,]+)\]\ ?)?
(?:(?P<code>(?:(?!Error\ Code).)*))?
(?P<error>Error\ Code:.+)?

in verbose mode, see a demo on regex101.com.

Broken down this says:

^                              # start of the line
(?:                            # non-capturing group
    \[                         # [
    (?P<d1>[\d,]+):            # digits and commas -> group "d1", followed by :
    (?P<d2>[\d,]+)             # group "d2
    \]\ ?                      # make the space optional
)?                             # make the whole group optional
(?:
    (?P<code>
        (?:(?!Error\ Code).)*) # everything until "Error Code"
     )?
(?P<error>Error\ Code:.+)?     # Error Code and anything that follows

In Python this could be:

import re
rx = re.compile(r"""...above expression...""", re.M | re.X)
for m in rx.finditer(string):
    print(m.group('error')) # or any other group

See a demo on ideone.com for the whole snippet.

edited Dec 21, 2018 at 10:06

answered Dec 21, 2018 at 8:02

Jan

43.3k11 gold badges57 silver badges87 bronze badges

1 Comment

user10754733 Over a year ago

this sol is good , but I want to change in this regex=(?:^[(\d+),(\s?[0-9:]+)](?:\s+(.+?)\s?)?(?:Error Code:.*)?$)|(?:()()()(Error Code:.*$)) and want this kind of output .I don't want to make new regex , thanks

Collectives™ on Stack Overflow

How to get a end string using regex in python?

2 Answers 2

2 Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related