var array = ['a', 'b', 'c']
function arrayTransform(array) {
if (array.lengths === 0) {
console.log("Empty")
} else {
console.log(array.join());
}
}
arrayTransform(array);the outcome should be 1.a, 2.b, 3.c I am getting abc
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3What is it in your code that you expect to prepend the numeric values to each array element?Pointy– Pointy2018-12-17 16:22:16 +00:00Commented Dec 17, 2018 at 16:22
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Nothing in your code indicates a number...Mike Tung– Mike Tung2018-12-17 16:23:01 +00:00Commented Dec 17, 2018 at 16:23
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array.map(function(e, i){return (i+1) + '.' + e}).join()XWX– XWX2018-12-17 16:23:52 +00:00Commented Dec 17, 2018 at 16:23
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4 Answers
Seems you wnat to add the index with the element. In that case use map function which will return an array and then use join to create the final string
var array = ['a', 'b', 'c']
function arrayTransform(array) {
if (array.lengths === 0) {
console.log("Empty")
} else {
return array.map((item, index) => {
return `${index+1}.${item}` // template literals
}).join()
}
}
console.log(arrayTransform(array));
1 Comment
Artem Metelskyi
Hey, just a quick question for me to better understand. Why did you put join outside of else statement? Is there a specific reason?
You could map the incremented index with the value and join it to the wanted style.
var array = ['a', 'b', 'c']
function arrayTransform(array) {
if (array.lengths === 0) {
console.log("Empty")
} else {
console.log(array.map((v, i) => [i + 1, v].join('.')).join());
}
}
arrayTransform(array);
Comments
You can use .reduce() to get the resultant string:
let data = ['a', 'b', 'c'];
let reducer = arr => arr.length ?
arr.reduce((r, c, i) => (r.push(`${i + 1}.${c}`), r), []).join() :
'Empty';
console.log(reducer(data));
console.log(reducer([]));
Comments
Welcome to Stackoverflow. Would you mind using the ES6 solution as shared below. Let me know if you need it in ES5.
let result = array.map((val, i) => i + 1 + "." + val);
console.log(result);
Comments
