A problem about VSCode for setting Python debuging

Question

vs code version:1.29.1（1.29.1）

python version:3.6.5

Launch.json:

     {
        "name": "Python",
        "type": "python",
        "pythonPath":"${config.python.pythonPath}", 
        "request": "launch",
        "stopOnEntry": true,
        "console": "none",
        "program": "${file}",
        "cwd": "${workspaceRoot}",
        "debugOptions": [
            "WaitOnAbnormalExit",
            "WaitOnNormalExit",
            "RedirectOutput"
        ],
        "env": {"name":"value"}
    }

workspacesettings:

     {
"python.pythonPath": "/usr/local/opt/python/libexec/bin/python",
"python.linting.pylintEnabled": true
     }

Extensions I downloaded.

When I test for debugging, I got failed.

result

It's said "You need to select a Python interpreter before you start debugging". But I actually choice one version shows in the lower left corner.

Any part is incorrect?

Terrence Poe · Accepted Answer · 2018-12-12 06:02:32Z

1

I edit as the code below and it works!!

{
"name": "Python: Current File (Integrated Terminal)",
"type": "python",
"request": "launch",
"program": "${file}",
"console": "integratedTerminal",
"stopOnEntry": true
}

answered Dec 12, 2018 at 6:02

Terrence Poe

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Comments

Sagun Raj Lage · Accepted Answer · 2018-12-12 03:33:54Z

0

The documentation that has been given here in the website of VS Code may be helpful. Did you try getting reference from here? https://code.visualstudio.com/docs/python/debugging

answered Dec 12, 2018 at 3:33

Sagun Raj Lage

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