How to get data from api response in Angular

Question

I'm using Angular 4, I've made a call to an api which returns an array of objects.

Then I tried to get specific data by referencing res.name but for some reason I get undefined so I tried res[0]name and res['name'] which returns only the first name but I want all the names from the array.

Here is my array:

[{"name":"joey","surname":"jackson","email":"[email protected]","phone":"0815342119"}, 
{"name":"Tim","surname":"Muller","email":"[email protected]","phone":""}, 
{"name":"Kim","surname":"Van Dam","email":"[email protected]","phone":""},
{"name":"Lyn","surname":"Davids","email":"[email protected]","phone":""}]

make your question a bit clear do you went to get the array of the name only ? — Hana Wujira
– Hana Wujira, Commented Dec 4, 2018 at 13:13
some of your values have null value so this may effect and show it as undefined — chethu
– chethu, Commented Dec 4, 2018 at 13:14

komron · Accepted Answer · 2018-12-04 13:13:30Z

1

Try using forEach to iterate over all elements of an array:

let res = [
{"name":"joey","surname":"jackson","email":"[email protected]","phone":"0815342119"},{"name":"Tim","surname":"Muller","email":"[email protected]","phone":""},{"name":"Kim","surname":"Van Dam","email":"[email protected]","phone":""},{"name":"Lyn","surname":"Davids","email":"[email protected]","phone":"08343435"}
];

res.forEach( (el) => {
  console.log(el.name);
})

answered Dec 4, 2018 at 13:13

komron

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Comments

Sajeetharan · Accepted Answer · 2018-12-04 13:07:37Z

0

You should use the dot operator when you are accessing property

it should be as,

res[0].name;

or

res[0]['name'];

answered Dec 4, 2018 at 13:07

Sajeetharan

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2 Comments

joe Over a year ago

that will return only the first name but i want all the names

J. Knabenschuh Over a year ago

so you have to loop or map over the items res.map(item => item.name)

Francesco G. · Accepted Answer · 2018-12-04 13:15:34Z

0

Assuming let people = [your array of objects]

In newer JS:

for (person of people) { 
    console.log(person.name) 
}

answered Dec 4, 2018 at 13:15

Francesco G.

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