Python script importing multiple files and save outputs

Question

I would like to open several files and save the outputs. This is the operation that I would like to script iteratively for {i}=76 files.txt. The reference_file.txt is always the same for each of the 76 files I want to manipulate.

import numpy as np
a=np.loadtxt('filename{i}.txt')
b=np.loadtxt('reference_file.txt')
np.savetxt('output{i}.txt', np.subtract(a,b))

and then end the script.

Eran Moshe · Accepted Answer · 2018-11-21 14:16:55Z

1

Looping python using a for command. range(0, 76) is a range object. To keep things simple it's like a list of 0 to 75. That means i will take the values of 0, 1, 2, .., 75 each iteration.

Extracted b out of the loop since it's not depended on i

Using string format to use i in the string. read about it here or here

import numpy as np

b = np.loadtxt('reference_file.txt')
for i in range(0, 76):
    a = np.loadtxt("filename{}.txt".format(i))
    np.savetxt("output{}.txt".format(i), np.subtract(a,b))

edited Nov 21, 2018 at 14:16

answered Nov 21, 2018 at 14:11

Eran Moshe

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3 Comments

Dan Over a year ago

I suggest better variable names than b and a. Also since Python 3.6: np.loadtxt(f"filename{i}.txt")

BlueSheepToken Over a year ago

I did not know that, and this is way more elegant than the format method I usually use

Eran Moshe Over a year ago

Also new to me! Thanks @Dan !

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