Powershell invoke-command $input

Question

I have a trouble.. Can someone help me? Here is my Code :

$A = '123'
$servers = 'computer1'
$Properties = [ordered]@{A = $A
                          servers = $servers     
                        }

$MyObject = New-Object -TypeName PSObject -Property $Properties

$MyObjec
...

$result = Invoke-Command -ComputerName Machine -UseSSL -InDisconnectedSession -ScriptBlock {
$MyObject.A
$MyObject.servers
$env:computername
}`
–InputObject $MyObjec -port 5986 -ConfigurationName myEndpoint -SessionOption @{OutputBufferingMode="Drop"} -Credential $credential | Receive-PSSession

$result

Question: Why the $result doesn't show anything about $MyObject?

It only show $MyObjec (not in the invoke-command) and $env:computername (in the invoke-command)

How can I fix it?

P.S this is really what I want to make, I want to get into multiple machine which in 6 different AD in the same time, but they should use different username, and I need $A in the remote machine to deal another thing.

$A = '123'
    $servers = 'computer1'
    $Properties = [ordered]@{A = $A
                              servers = $servers     
                            }

    $MyObject = New-Object -TypeName PSObject -Property $Properties

    $MyObjec
    ...

#Add
$servers@{'Machine1','Machine2','Machine3'}

Foreach ($servers in $servers) {

Star-Job {

$username = $servers+'account'

$password = $password

$credential = ....($username,$password)

    $result = Invoke-Command -ComputerName $servers -UseSSL -InDisconnectedSession -ScriptBlock {
    $MyObject.A
    $MyObject.servers
    $env:computername
    }`
    –InputObject $MyObjec -port 5986 -ConfigurationName myEndpoint -SessionOption @{OutputBufferingMode="Drop"} -Credential $credential | Receive-PSSession

    $result
}

}

I will try -Argument-List and param{} Beacase I try Start-Job with -Argument-List and $Using, there have an error. Thank u for your reply!

It's unclear to me what you want to achieve with your script. But I would always use $MyObject with a t at the end. — user6811411
– user6811411, Commented Nov 21, 2018 at 8:00
Thank you,In fact,my achievement is to run the invoke-command parallel in the same time.I edit my code clean! — Max BestWell
– Max BestWell, Commented Nov 21, 2018 at 11:11

TobyU · Accepted Answer · 2018-11-21 08:04:23Z

2

Because the part within -Scriptblock { ... } gets executed on the remote system and has therefore no access to the variables on the local system (different scope).

You can change that by passing the variables to the remote system using the -Argument-List parameter like this:

Invoke-Command -ComputerName Machine -ArgumentList $MyObject -ScriptBlock { 
    param($MyObject)

    $MyObject.A
}

Or use $using: to get access to the locally defined variables like that:

Invoke-Command -ComputerName Machine -ScriptBlock { 

    $using:MyObject.A
}

answered Nov 21, 2018 at 8:04

TobyU

3,9502 gold badges24 silver badges33 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Powershell invoke-command $input

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related