I have a function that takes a variable number of parameters and I have those parameters in an array. The function doesn't take the array as a parameter. What I want to do is destructure the array into the arguments of the function call. I am not sure how long the array is but I know it will be more than 3.
var array = ['a', 'b', 'c', 'd', ...etc]
doit(arr[0], arr[1], arr[2], ...etc)
function doit( a, b, ...c){
//do stuff
}
Sounds like you should just spread array into the call of doit:
doit(...array);
Note that this is called spread (or "spread syntax"), which is not destructuring. Destructuring involves either creating a new variable, or assigning to an existing variable.
The older method would be to use apply:
doit.apply(undefined, array);
function doit(a, b, ...c)), which is valid even if you may have just meant it as shorthand, if you do the above you'd get the first array element as a, the second as b, and the rest of them in as an array in c (that declaration for c is called a rest parameter).
One way would be to use the special variable arguments inside any javascript function. You will gain access to all arguments, regardless of their count.
var arr1 = ['a', 'b', 'c', 'd', 'e', 'f'];
var arr2 = ['A', 'B', 'C'];
doit(arr1); // one argument: [a,b,c,d,e,f]
doit(arr2); // one argument: [A,B,C]
doit(arr1[0], arr2[1], 'anything', -3.1); // four arguments: a, B, 'anything', -3.1
function doit(){
for(var i=0; i<arguments.length; i++) {
console.log("argument " + i + " is : " + arguments[i]);
}
}
