getting index of nan values in numpy array

Question

Getting the index of nan values from where condition and passing it to original array but it is returning empty

#Input
url = 'https://archive.ics.uci.edu/ml/machine-learning-databases/iris/iris.data'
iris_2d = np.genfromtxt(url, delimiter = ',', dtype = 'float')# random number from 0 to 150 as high is none
iris_2d[np.random.randint(150, size = 20), np.random.randint(4, size = 20)] = np.nan


( iris_2d[np.where(iris_2d[a,b]==np.nan)])

By definition nan!=nan which is why your code does not work. — Paul Panzer
– Paul Panzer, Commented Nov 9, 2018 at 9:18

Siddharth Satpathy · Accepted Answer · 2018-11-09 08:54:36Z

2

I downloaded the data from the url that you mentioned, and saved it as 'iris_data.txt'. Try the following code. It gives you indices of nan in the numpy array iris_2d.

import numpy as np

iris_2d = np.genfromtxt('iris_data.txt', delimiter = ',', dtype = 'float')

nan_indx = np.argwhere(np.isnan(iris_2d))

print nan_indx.shape
print " " 
print nan_indx[0:5,:]

Output:

(150, 2)

[[0 4]
 [1 4]
 [2 4]
 [3 4]
 [4 4]]

answered Nov 9, 2018 at 8:54

Siddharth Satpathy

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