How to loop over array of objects and check if name exists?

Question

I have array of objects with about 500 records. I would like to loop trough the array of objects and check if object name is equal to one of the elements. Here is example of my array of objects:

data = [
      {
        "row": 23,
        "code": "ERT"
      },
      {
        "row": 45,
        "code": "TTR"
      },
      {
        "row": 90,
        "code": "CXZ"
      }
    ];

Here is what I tried so far:

data.some(function (obj) {
    if(obj.name === "code"){
        return obj[name]; // Return value if name exists
    }
});

I would like to check if name exists in the object. If does, pull the value for that name. My code will produce undefined in the console. Can someone help with this? Is there a way to achieve this?

clearshot66 · Accepted Answer · 2018-11-01 18:57:49Z

1

Something like so:

data = [
      {
        "row": 23,
        "code": "ERT"
      },
      {
        "row": 45,
        "code": "TTR"
      },
      {
        "row": 90,
        "code": "CXZ"
      }
    ];


$.each(data, function(index,v) {
 $.each(v, function(key,val) {
    if(key == "code")
       console.log(val)
    }
 });
});

Without inner loop:

for (var key in data){

  if(key == "code"){
     console.log(key)
  }
}

edited Nov 1, 2018 at 18:57

answered Nov 1, 2018 at 18:55

clearshot66

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9 Comments

espresso_coffee Over a year ago

I was trying to avoid inner loop for efficiency purposes. Do you have any experience with the solution above? How that will affect the large amount of data?

clearshot66 Over a year ago

Just fixed, you can use second example for no loop. I use it but I also use under 100 objects typically. Try it and find out. Simple google of "Search a JS object" yields 100s of results

clearshot66 Over a year ago

stackoverflow.com/questions/7700987/…

espresso_coffee Over a year ago

Second solution will only provide element number/position. I need the actual name of each element in the object. I hope this make sense. When I loop through I should get row and code for the name.

clearshot66 Over a year ago

@espresso_coffee I'm using jsbin right now and that solution returns "ERT" ,"TTR","CXZ". It gives the actual name. editing to show key too then now.

|

Dacre Denny · Accepted Answer · 2018-11-01 19:08:58Z

1

If I understand your question correctly, then you can achieve this by .filter(), where for each item being filtered, your examine the item's keys (via Object.keys()) to see if it contains any of the keys that you're searching/filtering against:

var namesToCompare = ['name', 'code'];

var data = [
      {
        "row": 23,
        "code": "ERT"
      },
      {
        "row": 45,
        "code": "TTR"
      },
      {
        "row": 90,
        "code": "CXZ"
      },
      {
        "row": 91,
        "code": "ABC", 
        "name" : "code"
      }
    ];
    
var result = data
.filter(item => Object
    .keys(item)
    .find(key => namesToCompare.includes(key)))

console.log('items with keys', namesToCompare, 'in list', result);

edited Nov 1, 2018 at 19:08

answered Nov 1, 2018 at 18:52

Dacre Denny

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1 Comment

Mit Jacob Over a year ago

Can we filter by Value instead of Key here?

Ariel · Accepted Answer · 2018-11-01 19:11:48Z

1

You can do something like this:

const name = "code";
const data = [
      {
        "row": 23,
        "code": "ERT"
      },
      {
        "row": 45,
        "code": "CXZ"
      },
      {
        "row": 90,
        "code": "TTR"
      },
      {
        "row": 190,
        "code": "CXZ"
      }
    ];

const values = [];

data.forEach(element => {
	if (Object.keys(element).includes(name)) {
  	values.push(element[name]);
  }
});
    
console.log(values);

Object.keys grab all the keys of the object, and then includes searchs the "name" in those keys.

edited Nov 1, 2018 at 19:11

answered Nov 1, 2018 at 19:01

Ariel

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4 Comments

espresso_coffee Over a year ago

What if for example I have array of name that I have to compare to the Object.keys(element)? Basically instead of comparing just one name, I have to compare multiple names.

Ariel Over a year ago

Actually that wasn't part of your question, but... you need another loop to do that.

espresso_coffee Over a year ago

I know, my apologies. That's what I realized. Seems like not very efficient solution.

Dacre Denny Over a year ago

@espresso_coffee does my answer help with this?

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