Here is my below code that works fine. 'cluster_name' is a string variable that will hold some text.
if 'abc' not in cluster_name or 'xyz' not in cluster_name:
print "true"
else:
print "false"
i was looking to make the if condition even more simpler , something like this:
if 'abc' or 'xyz' not in cluster_name:
print "true"
else:
print "false"
is there a simpler way to do this?
Your approach looks fine, but doesn't generalize well (imagine if you had to check ten substrings instead of just two). Try any.
substrings = ['abc', 'xyz']
if any(substr not in cluster_name for substr in substrings):
print("true")
else:
print("false")
abc and xyz are present in cluster_name. Is this what you expect?
import re
print (re.search('abc|xyz',cluster_name) is not None)
is simpler. It does not need if or else; you can extend the search string as long as you want (although within reasonable limits, no doubt). re.search returns None if the regex does not match and you want the inverse of that, hence not None.
