Efficient way to create array of integer days from today in PHP

Question

I'm trying to build an array of days using date(z) days of year format, starting with today, and stepping through a set number of days.

I've figured out a solution to this, but it doesn't feel like it's the most efficient, maybe there is a built-in function in PHP for this.

Current solution:

$today = date(z);
$count = 3;
$array = array();
$i = 0;
while ($i < $count) {
  $array[] = $today + $i;
  $i++;
}

print_r($array);

Outputs correctly to this: Array ( [0] => 297 [1] => 298 [2] => 299 )

Any other better solutions?

I wouldn't call this a bad approach. Maybe a for loop would be better than the while. — maio290
– maio290, Commented Oct 25, 2018 at 16:20
What's the desired behavior when $count is high enough to cross years? — Patrick Q
– Patrick Q, Commented Oct 25, 2018 at 16:22
@PatrickQ hadn't considered it, in my use case that would not be possible. — Jeff Solomon
– Jeff Solomon, Commented Oct 25, 2018 at 16:31

mickmackusa · Accepted Answer · 2018-12-02 06:04:33Z

3

range — Create an array containing a range of elements

So let's take today:

$today = date('z');
$range = range($today, $today + $count);

mickmackusa♦

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answered Oct 25, 2018 at 16:21

treyBake

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2 Comments

Would range($today, $today+$count); (or similar) be better?

@NigelRen thanks for that; for my use case I need the array ONLY to have the days specified, not the entire 365 so this would work better.