how to get output of awk into array in shell script

Question

I am comparing two files and displaying the lines which are not similar, when I just keep

echo $(awk 'FNR==NR{f[$0]+=1; next} !($0 in f)' $file1 $file2)

I am able to get the values.

When I try to do the same by passing into array , I am getting ":command not found" error

declare -a myarr=()
myarr=$("$(awk 'FNR==NR{f[$0]+=1; next} !($0 in f)' $file1 $file2 )")

Please help , thanks in advance.

Why are you doing +=1? Nothing in your code uses it afterwards. — Ed Morton
– Ed Morton, Commented Oct 24, 2018 at 15:29

hek2mgl · Accepted Answer · 2018-10-24 14:40:55Z

2

Remove the quotes plus the leading dollar:

myarr=$("$(awk 'FNR==NR{f[$0]+=1; next} !($0 in f)' $file1 $file2 )")

should be

myarr=($(awk 'FNR==NR{f[$0]+=1; next} !($0 in f)' $file1 $file2))

Check:

Btw, your awk command won't print lines which are unique to file1. Probably the comm command is what you want, but note that comm expects sorted input:

comm -13 <(sort "${file1}") <(sort "${file2}")

edited Oct 24, 2018 at 14:40

answered Oct 24, 2018 at 14:30

hek2mgl

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