Check if variable exist with dynamic variable name and dynamic key name and deepness

Question

what is the correct syntax to use isset with a dynamic variable name and dynamic key name, without writing the keyname in braces.

Example:

$ab[0] = 'test';
$var1="ab";
$var2="[0]";
$var3="0";

//This works
if (isset(${$var1}[0])){
   echo "success";
}

//This works too
if (isset(${$var1}[$var3])){
   echo "success";
}


//But this doesn't.
if (isset(${$var1}$var2)){
   echo "success";
}

What can I do that the 3rd example works? I can't use the first or second example, because I dont't know how many subarrays are inside the array.

This might be an example of an XY problem (meta.stackexchange.com/q/66377/159630). Could you back up a few steps and explain your goal to us a bit more? — waterloomatt
– waterloomatt, Commented Oct 19, 2018 at 17:22
seems like you should use other functions instead of this. Things like is_array to determine what to do, instead of trying to see if it is an array by variable varibles — Ice76
– Ice76, Commented Oct 19, 2018 at 17:25

Marty1452 · Accepted Answer · 2018-10-19 17:21:37Z

0

You cannot type brackets to variable.

Here is code:

<?php
$ab[0] = 'test';
$var1="ab";
$var2="0";
$var3="0";

//This works
if (isset(${$var1}[0])){
   echo "success";
}

//This works too
if (isset(${$var1}[$var3])){
   echo "success";
}


//This works too
if (isset(${$var1}[$var2])){
   echo "success";
}
?>

answered Oct 19, 2018 at 17:21

Marty1452

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