I don't know how to add multiple values for a struct in C using a pointer. Here's my code and the gcc error is:
error: assignment to expression with array type
(p+0)->name = "Teszt";
#include <stdio.h>
typedef struct{
char name[101];
int born_in;
} paciens;
int main(){
paciens *p;
int n = 5;
p = (paciens*) malloc(n * sizeof(paciens));
(p+0)->name = "Test";
(p+0)->born_in = 1992;
printf("Name: %s ; Born in: %d\n", (p+0)->name, (p+0)->born_in);
return 0;
}
You cannot assign to an array, but you can assign to a struct, which contains an array:
p[0] = (paciens) { .name = "Test", .born_in = 1992};
will do this. This is called a compound literal.
Also note that you forgot to #include <stdlib.h> for malloc.
The member name is an array. You can't assign to an array, only copy to it. To copy a string use strcpy:
strcpy(p[0].name, "Test");
Any good book, tutorial or teacher should have mentioned this.
char strings in C are really called null-terminated byte strings. It's easy to implement your own variant of strcpy with a simple loop if you remember the proper name. But I fail to see why anyone would want that.
(p+0)->name = "Test";==>strcpy((p+0)->name, "Test");