JSON accessing multiple instances inside of an array

Question

I am using JSONDecoder to access JSON data through an API. Within this JSON Data are several [arrays]. I am running into a problem of accessing each instance that a key appears.

Here is the code:

var details = [Details]()
var production = [Production]()

struct Details: Codable {
    let title: String
    let poster_path: String?
    let id: Int?
    let production_companies: [Production]
}

struct Production: Codable {
    let name: String
}


let task = session.dataTask(with: request, completionHandler: { (dataOrNil, response, error) in
        if let data = dataOrNil {
            do { let details = try! JSONDecoder().decode(Details.self, from: data)

let production = details.production_companies
print(production)

 }
        }

    })

Here is what print(production) prints to the console:

[Film_Bee.DetailsView.Production(name: "Columbia Pictures"), Film_Bee.DetailsView.Production(name: "Marvel Entertainment"), Film_Bee.DetailsView.Production(name: "Sony Pictures")]

What I'm trying to do is access each name within the array. I know to access the first one I can use production.first?.name but if I am unsure how to access each one to place into a single label.

Do you want to add three companies' names into a single UIlabel or three UIlabel? — Razib Mollick
– Razib Mollick, Commented Oct 13, 2018 at 4:42
My answer to your previous question shows how to get all items in an array. — vadian
– vadian, Commented Oct 13, 2018 at 7:52

Razib Mollick · Accepted Answer · 2018-10-13 05:29:49Z

1

Prashant points already. I just additionally add a little bit which may help you.

I believe you know swift loop like for or forEach to see your string list

production.forEach { model in
    print(model.name)
}

For your problem, you need to join your string list. As you need to update UI, use DispatchQueue.

let productionList = production.map{$0.name}
let strings = productionList.joined(separator: " ") //use "\n" if you wish new line
print("stringList: \(strings)")
DispatchQueue.main.async() {  
 yourLabel.text = strings
}

answered Oct 13, 2018 at 5:29

Razib Mollick

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Comments

Prashant Tukadiya · Accepted Answer · 2018-10-13 04:43:35Z

1

Try this

let production = details.production_companies.map{$0.name}

What production_companies is Array. and you have to iterate over it using map and get its name that is simple to understand right ?

Not Related but don't use try! you should properly handle error use do try catch block

answered Oct 13, 2018 at 4:43

Prashant Tukadiya

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