Transform a JsonArray into an ArrayList

Question

I have this json that i got using the YoutubeAPI :

{
 "items": [
  {
   "id": {
    "videoId": "ob1ogBV9_iE"
   },
   "snippet": {
    "title": "13 estrellas ",
    "description": "Pueden encontrar estas "
   }
  },
  {
   "id": {
    "videoId": "o9vsXyrola4"
   },
   "snippet": {
    "title": "Rayos Cósmicos ",
    "description": "Este es un programa piloto "
   }
  }
]
}

i want to save the fiel "id" on an ArrayList but i have some problems this is the code im using:

JSONArray jsonArray = myResponse.getJSONArray("items");

In this line im creating an JSONarray with the JSONobject i created first

ArrayList<String> list = new ArrayList<>();
for (int i = 0; i < jsonArray.length(); i++) {
    try {
        JSONObject json = jsonArray.getJSONObject(i);

        list.add(json.getString("videoID"));
    } catch (JSONException e) {
        e.printStackTrace();
    }
}

My question is how can i access to this field? and how can i save it

the videoId is a subProperty of an object called id

bhspencer
– bhspencer

2018-10-12 17:40:33 +00:00
Commented Oct 12, 2018 at 17:40 — bhspencer
– bhspencer, Commented Oct 12, 2018 at 17:40

azurefrog · Accepted Answer · 2018-10-12 17:40:29Z

1

You've got two main issues. The first is that "videoID" and "videoId" are not the same string. So you're checking for a key that doesn't exist.

Your second problem is that the "videoId" key doesn't exist in the top level object, it's inside the "id" object, so you need to drill down an extra layer to get it:

    JSONArray jsonArray = myResponse.getJSONArray("items");
    ArrayList<String> list = new ArrayList<>();
    for (int i = 0; i < jsonArray.length(); i++) {
        try {
            JSONObject json = jsonArray.getJSONObject(i);
            JSONObject id = json.getJSONObject("id");

            list.add(id.getString("videoId"));
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

    System.out.println(list);  // [ob1ogBV9_iE, o9vsXyrola4]

answered Oct 12, 2018 at 17:40

azurefrog

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Comments

sagarr · Accepted Answer · 2018-10-12 17:38:26Z

0

Try with correct case for videoId, like

list.add(json.getString("videoId"));

answered Oct 12, 2018 at 17:38

sagarr

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