phpunit expectException() wrong exception name

Question

When I run PHPUnit 6.5.13. and have a test method following this example PHPUnit Testing Exceptions Documentation

public function testSetRowNumberException()
{
    $this->expectException(\InvalidArgumentException::class);
    $result = $this->tableCell->setRowNumber('text');

}

that tests this method:

public function setRowNumber(int $number) : TableCell
{
    if (!is_int($number)) {
        throw new \InvalidArgumentException('Input must be an int.');
    }
    $this->rowNumber = $number;

    return $this;
}

I got this failure:

Failed asserting that exception of type "TypeError" matches expected exception "InvalidArgumentException".

the question is why "TypeError" is taken to assertion and how to make assertion use InvalidArgumentException?

Jimmix · Accepted Answer · 2018-10-12 17:29:27Z

2

Got it. The thing is I used typing set to int that's why the code didn't even reach the thow command.

it works if tested method is without set typing to int:

public function setRowNumber($number) : TableCell
{
    if (!is_int($number)) {
        throw new \InvalidArgumentException('Input must be an int.');
    }
    $this->rowNumber = $number;

    return $this;
}

or when the test has TypeError

public function testSetRowNumberException()
{
    $this->expectException(\TypeError::class);
    $result = $this->tableCell->setRowNumber('text');
}

I'll stay with the second example.

edited Oct 12, 2018 at 17:29

answered Oct 12, 2018 at 17:23

Jimmix

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