I need to create string value depend on the length of array

Question

I need to create a string value depending on the length of the array.

var array = ["left", "right", "top", "bottom"];
//list contain array of Object
 list.forEach((po) => {

//for example if the length of the list is 10. i need to generate the string for each loop like this 

// "left0"   for 1 loop i need this value 
// "right0"  for 2 loop i need this value
// "top0"      for 3 loop i need this value
// "bottom0"   for 4 loop i need this value

// "left1"     for 5 loop i need this value
// "right1"   for 6 loop i need this value
// "top1"     for 7 loop i need this value
// "bottom1"     for 8 loop i need this value

// "left2"   for 1 loop i need this value 
// "right2"  for 2 loop i need this value
}

Please help me with this issue. i am finding difficult generating string along with the number at the last and the left, right, top, bottom should be in the order and number should change after 5 loop as shown

for(var i=0; i<list.length; i++){ ... = array[i] + ParseInt(i/array.length); } — Aleksey Solovey
– Aleksey Solovey, Commented Sep 27, 2018 at 10:10

Pranav C Balan · Accepted Answer · 2018-09-27 10:10:25Z

3

You can do it using the index of list item and length of the array.

var array = ["left", "right", "top", "bottom"];

// Dummy list array
var list = new Array(10).fill(0);

list.forEach((po, i) => {
  // based on index of list calculate position in array
  // by using remainder operator
  var j = i % array.length,
    // get repetion count by simple dividing by the length
    c = Math.floor(i / array.length);
  console.log(array[j] + c)
});

answered Sep 27, 2018 at 10:10

Pranav C Balan

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Comments

Diego · Accepted Answer · 2018-09-27 10:28:09Z

0

Using new ECMAScript objects such as arrow functions and the fill prototype method, along with the new let and const variable types, you can do it like this:

let instructions = ['left', 'right', 'top', 'bottom'];
const ARRAY_LEN = 10;
const DUMMY_ELEM = 0;
let dummyArray = new Array(ARRAY_LEN).fill(DUMMY_ELEM);
dummyArray.map((element, index) => {
    const AUX_INDEX = index % instructions.length;
    console.log(instructions[AUX_INDEX] + Math.floor(index / instructions.length));
})

EDIT: I used map but you could use, of course, forEach or maybe, depending on your specific problem, even the Array.prototype.every method.

edited Sep 27, 2018 at 10:28

answered Sep 27, 2018 at 10:20

Diego

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Comments

Arnab Das · Accepted Answer · 2018-09-27 10:28:38Z

0

In case you just want only one value depending on the array length. This might help you:

var array = ["left", "right", "top", "bottom"];
var list = [1,2,3,4,5,6,7];
var index = (list.length - 1) % array.length;
var postfix = Math.floor(list.length / array.length);
var result = array[index] + postfix;
console.log(result);

In case you need list of strings:

var array = ["left", "right", "top", "bottom"];
var list = [1,2,3,4,5,6,7];
var result = list.map((item, index) => array[index % array.length] + Math.floor(index / array.length));
console.log(result);

edited Sep 27, 2018 at 10:28

answered Sep 27, 2018 at 10:22

Arnab Das

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