170

I'd like to get a string literal union from an enum.

For this enum…

enum Weekday {
    MONDAY = 'mon',
    TUESDAY = 'tue',
    WEDNESDAY = 'wed'
}

… I'd like to get this:

type WeekdayType = 'mon' | 'tue' | 'wed';

I tried typeof keyof Weekday but that resulted in 'MONDAY' | 'TUESDAY' | 'WEDNESDAY'. Feel like the solution might have to do with mapped types but I can't seem to wrap my head around it.

How do I do this?

2
  • That's unfortunate! Commented Sep 19, 2018 at 1:18
  • @jcalz when people 'answer' in comments like you did, the answers cannot be edited by the community. It's a pity, as this question can now be solved, but people coming onto this question will first read your (then correct, now incorrect) comment and may be mislead as a result. Commented Aug 19, 2023 at 9:37

5 Answers 5

244

See TS4.1 ANSWER:

type WeekdayType = `${Weekday}`;

PRE TS-4.1 ANSWER:

This can't be done programmatically... you're trying to convert the type Weekday, which is Weekday.MONDAY | Weekday.TUESDAY | Weekday.WEDNESDAY, to the type WeekdayType which is "mon" | "tue" | "wed". This conversion is a form of widening, since Weekday is a subtype of WeekdayType:

type WeekdayExtendsWeekdayType = 
  Weekday extends WeekdayType ? true : false
// type WeekdayExtendsWeekdayType = true

Unfortunately the compiler doesn't give you a handle to remove an "enum"-ness from the enum type and leave you with plain literal types.


So, workarounds? Maybe you don't actually need an enum, but can make do with an object whose property values are string literals:

const lit = <V extends keyof any>(v: V) => v;
const Weekday = {
  MONDAY: lit("mon"),
  TUESDAY: lit("tue"),
  WEDNESDAY: lit("wed")
}
type Weekday = (typeof Weekday)[keyof typeof Weekday],

If you inspect it, the value named Weekday behaves like an enum object:

console.log(Weekday.TUESDAY); // tue

while the type named Weekday behaves like the union of string values "mon" | "tue" | "wed" that you were calling WeekdayType:

const w: Weekday = "wed"; // okay
const x: Weekday = "xed"; // error

So in this workaround, there is no "enum"-ness, and therefore no need to distinguish the type Weekday from the type WeekdayType. It's a little different from an actual enum (which includes types like Weekday.MONDAY, which you'd have to represent as the cumbersome typeof Weekday.MONDAY or create a different type alias for it), but it might behave similarly enough to be useful. Does that work for you?

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6 Comments

Update: since typescript 3.4, special lit function is no longer needed. You can use const assertions instead
curios question @jcalz. What does <V extends keyof any> do? it prevents widening any kind of string/number literal ? thanks!
is there a way to do the opposite? Get a string enum from a type that is a union of string literals?
@Pablo I don't think so.
type WeekdayType = `${Weekday}`; is wicked
|
76

TypeScript 4.1+:

As mentioned, this can be achieved by using Template Literal Types like so:

type WeekdayType = `${Weekday}`;

TypeScript 3.4+:

Following up on @jcalz answer and the comment from @just-boris, here's an example with const assertions:

const Weekday = {
  MONDAY: "mon",
  TUESDAY: "tue",
  WEDNESDAY: "wed",
} as const;

type Weekday = (typeof Weekday)[keyof typeof Weekday];

1 Comment

That should work but has a limitation. ``` type Weekday1 = (typeof Weekday)[keyof typeof Weekday]; type Weekday2 = ${Weekday}; const day1: Weekday1 = Weekday.MONDAY; => works const day2: Weekday2 = Weekday.MONDAY; => works const day3: Weekday1 = 'mon' => does not work const day4: Weekday2 = 'mon'; => works ```
71

With Typescript 4.1, it can be done!

enum Weekday {
  MONDAY = 'mon',
  TUESDAY = 'tue',
  WEDNESDAY = 'wed'
}

type WeekdayType = `${Weekday}`;

And for number enums, thanks to @okku:

enum ThreeDigits {
  ZERO = 0,
  ONE = 1,
  TWO = 2
}

type ThreeDigitsType = `${ThreeDigits}` extends `${infer T extends number}` ? T : never;

8 Comments

An easier way to to this is: type WeekdayUnion = ${Weekday}; That's it!
any luck getting this to compile with ts-node?
@MichaelG yes, you just need to update your typescript version to 4.1 in your project's package.json in your dev dependencies
Could someone provide documentation for this behaviour plz?!
It does work with number enums, with some extra work: type WeekdayType = ${Weekday}` extends ${infer T extends number} ? T : never;`
|
2

Here is a simple way to do that.

Here the example of how to convert a Typescript enum to a union type

export enum PaymentSystemEnum {
  APPLE = 'APPLE',
  GOOGLE = 'GOOGLE'
}

And it’s pretty easy

type = `${PaymentSystemEnum}`; // "APPLE" | "GOOGLE"

Reference Link

1 Comment

this way of extraction union out of enum is brilliant.
1

Typescript 4.8+ has some new features that we can use here. It works with string enums, number enums, and mixed enums too.

Typescript Playground

export type EnumToPrimitiveUnion<T> = `${T & string}` | ParseNumber<`${T & number}`>;
type ParseNumber<T> = T extends `${infer U extends number}` ? U : never;

export function typeCastEnum<E>(value: EnumToPrimitiveUnion<E>): E {
  return value as E;
}

enum Enum1 {
  A = 'a',
  B = 'b',
  X = 5,
}
enum Enum2 {
  A = 'a',
  C = 'c',
  Y = 6,
}
enum Enum3 {
  A2 = 'a',
  B2 = 'b',
  X2 = 5,
}


type PrimitiveEnum1 = EnumToPrimitiveUnion<Enum1>; // 'a' | 'b' | 5
typeCastEnum<Enum1>(Enum2.A); // ok, 'a' fits
typeCastEnum<Enum1>('b'); // ok
typeCastEnum<Enum1>(5); // ok
typeCastEnum<Enum1>(Enum3.A2 as Enum3); // ok, all values of Enum3 fit

// @ts-expect-error
typeCastEnum<Enum1>(Enum2.C); // err, 'c' does not fit
// @ts-expect-error
typeCastEnum<Enum1>('c'); // err, 'c' does not fit
// @ts-expect-error
typeCastEnum<Enum1>(Enum2.A as Enum2); // err, some values of Enum2 do not fit
// @ts-expect-error
typeCastEnum<Enum1>(Enum2.Y); // err
// @ts-expect-error
typeCastEnum<Enum1>(99); // err
// @ts-expect-error
typeCastEnum<Enum1>('foo'); // err

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