Python not finding None in a numpy array

Question

Today python stopped finding None in a numpy array. My code breaks because of the following. Any clue appreciated.

In [36]: abc = np.array([3,2,None])

In [37]: None is abc[-1]
Out[37]: True

In [38]: None in abc
/Users/py/htrans.py:1: FutureWarning: comparison to `None` will result in an    elementwise object comparison in the future. #!/usr/bin/env python3
Out[38]: False

In [39]: abc==None
/Users/py/htrans.py:1: FutureWarning: comparison to `None` will result in an elementwise object comparison in the future. #!/usr/bin/env python3
Out[39]: False

sys.platform
Out[42]: 'darwin'

sys.version
Out[43]: '3.5.1 |Anaconda 4.0.0 (x86_64)| (default, Dec  7 2015, 11:24:55) \n[GCC 4.2.1 (Apple Inc. build 5577)]'

np.version.version
Out[44]: '1.10.4'

What does type(None) show and what does None is seq[wave:wave+lead][-1] show? — Jon Clements
– Jon Clements, Commented Sep 15, 2018 at 15:13
ipdb> type(None) <class 'NoneType'> ipdb> None is seq[wave:wave+lead] False ipdb> — andrea m.
– andrea m., Commented Sep 15, 2018 at 15:15
Curious... and what does seq[wave:wave_lead] == None give? — Jon Clements
– Jon Clements, Commented Sep 15, 2018 at 15:19

bunbun · Accepted Answer · 2018-09-15 15:40:22Z

2

Link: https://github.com/numpy/numpy/issues/1608

According to the link, this bug was reported and fixed in the 1.13.0 release of Numpy.

A quick workaround you can use is:

any(elem is None for elem in abc)

answered Sep 15, 2018 at 15:40

bunbun

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