Creating an API to execute a python script

Question

I have a python script app.py in my local server (path=Users/soubhik.b/Desktop) that generates a report and mails it to certain receivers. Instead of scheduling this script on my localhost, i want to create an API which can be accessed by the receivers such that they would get the mail if they hit the API with say a certain id. With the below code i can create an API to display a certain text. But, what do i modify to run the script through this? Also if i want to place the script in a server instead of localhost, how do i configure the same?

from flask import Flask

app = Flask(__name__)

@app.route("/")
def hello():
    return ("hello world")


if __name__ == '__main__':
    app.run(debug=True)

Python Version is 2.7

Your code isn't really related to what you're actually asking. — Mad Physicist
– Mad Physicist, Commented Sep 3, 2018 at 6:03

techytushar · Accepted Answer · 2018-09-03 06:00:49Z

3

A good way to do this would be to put the script into a function, then import that function in your Flask API file and run it using that. For hosting on a web server you can use Python Anywhere if you are a beginner else heroku is also a good option.

answered Sep 3, 2018 at 6:00

techytushar

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Alex · Accepted Answer · 2018-09-03 06:03:44Z

2

If you are tying to achieve something using Python-Flask API than you can have a close look at this documentations and proceed further https://www.flaskapi.org/, http://flask.pocoo.org/docs/1.0/api/

Apart from these here are few basic examples and references you can refer for a quickstart :

1-https://programminghistorian.org/en/lessons/creating-apis-with-python-and-flask

2- https://flask-restful.readthedocs.io/en/latest/

3- https://realpython.com/flask-connexion-rest-api/

answered Sep 3, 2018 at 6:03

Alex

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Kedarnag Mukanahallipatna · Accepted Answer · 2018-09-03 06:05:54Z

1

You could do something like this

from flask import Flask
from flask_restful import Resource, Api

app = Flask(__name__)
api = Api(app)

class ExecuteScript:
  def printScript:
    return "Hello World"

api.add_resource(ExecuteScript, '/printScript')

if __name__ == '__main__':
    app.run(debug=True)

answered Sep 3, 2018 at 6:05

Kedarnag Mukanahallipatna

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