I have two different length c++ strings.
string str1 = "01001110 01100001 01101101 01100101"
string str2 = "00000000 00000000 00000011"
I need to xor str1 and str2 and store the result in a new string
string xor_string = str1 ^ str2
So, is it possible to xor two different length strings, and to store it into another string ?
I have searched for it but I didn't get it.
Can anyone tell me, how to do it?
Something like this:
#include <string>
#include <iostream>
#include <bitset>
#include <algorithm>
std::bitset<32> to_bitset(std::string s)
{
auto binary = [](char c) { return c == '0' || c == '1'; };
auto not_binary = [binary](char c) { return !binary(c); };
s.erase(std::remove_if(begin(s), end(s), not_binary), end(s));
return std::bitset<32>(s);
}
std::string to_string(std::bitset<32> bs)
{
return bs.to_string();
}
int main()
{
std::string str1 = "01001110 01100001 01101101 01100101";
std::string str2 = "00000000 00000000 00000011";
auto result = to_string(to_bitset(str1) ^ to_bitset(str2));
std::cout << result << std::endl;
}
expected output:
01001110011000010110110101100110
std::string
result is a std::string
std::bitset I recommend you opening a new question (since this one is answered and this new information would invalidate the good answer) and adding your implementation of operator^ and explain the problem you are having with your code.str1 in my case` and str2 is a static string. Means I want to make std::string result = std::string str1 Is It possible ?And if possible then what should I do? Now I have kept My both string are of equal length = 64You could always walk through or iterate through the string, and place the result into a new string.
std::string str1 = "01001110 01100001 01101101 01100101";
std::string str2 = "00000000 00000000 00000011";
//...
std::string result;
const char c = ((str1[i] - '0') ^ (str2[i] - '0')) + '0';
result += c;
The fundamental issue is that you need to make the strings of equal length or change your algorithm to handle strings of different length.
For example, do you repeat str2 when str1 is longer or do you prefix str2 with '0'? This you will need to answer for yourself.
str1 in my case` and str2 is a static string. Means I want to make std::string result = std::string str1
xoroperation is not defined on strings (because they usually contain other characters than just zeros and ones), you will have to define it yourself.^operator however you want to (see operator overloading). What type of behavior are you looking for when the lengths of the strings are unequal?xor_stringto be?