Java instantiate class from string

Question

I have the following,

public interface SuperbInterface
public class A implements SuperbInterface
public class B extends A
public class C extends B

I want to instantiate C but I seems to be getting B, what did I do wrong?

Class classz = Class.forName("C");
SuperbInterface superb = (SuperbInterface)classz.newInstance();

//Here when I debug it seems to be going to B.doWork() methods instead of C.doWork().
superb.doWork();

have you overriden doWork in C ?? please show the relevant code fully — Jigar Joshi
– Jigar Joshi, Commented Mar 3, 2011 at 8:24

Suraj Chandran · Accepted Answer · 2011-03-03 08:25:04Z

5

The only thing I can think of is that you haven't overridden doWork() in C.

Maybe you have tried ot override but with some spelling mistake in method name or wrong parameters?

answered Mar 3, 2011 at 8:25

Suraj Chandran

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1 Comment

Rosdi Kasim Over a year ago

As it turns out there is an obsolete jar in the build path, it so happens in this jar C has not yet override B's doWork. duh!

TofuBeer · Accepted Answer · 2011-03-03 08:40:55Z

1

Assuming you are using a newer version of Java add @Override to the doWork method. If you have incorrectly overriden the method the compiler will then let you know.

answered Mar 3, 2011 at 8:40

TofuBeer

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Comments

Tim Bender · Accepted Answer · 2011-03-03 08:28:05Z

0

Are you sure that C overrides the doWork method? Based on the question as it is posed it is perfectly reasonable/legal to expect that as part of extending B, C does not provide its own implementation for doWork and instead relies on the one provided the superclass B.

answered Mar 3, 2011 at 8:28

Tim Bender

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Comments

Shiv · Accepted Answer · 2011-03-03 08:50:48Z

0

I see the outcome:

A's do work

whats the things you are expecting ?

answered Mar 3, 2011 at 8:50

Shiv

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