Bash script Set variable in loop [duplicate]

Question

I want to run a for loop for all strings in a variable (one by one). When I echo my variable it is like this

A=(curl -s 'localhost:9200/something)
echo "$A"

emits:

sss
ddd
fff
ggg
hhh

My for loop is like this:

for i in "${A[@]}"; do
  echo "$i"
  echo test
 done

But loop just run one time and print all data, instead of putting test after each item:

sss
ddd
fff
ggg
hhh
test

Try simple echo $A | while read line; do echo $line; done. — 0andriy
– 0andriy, Commented Jul 28, 2018 at 6:31
@0andriy thanks. it work like this: echo "$A" | while read line; do echo "$line"; done — hamid bayat
– hamid bayat, Commented Jul 28, 2018 at 6:47
Better store them in an actual array: a=("sss" "ddd"); for i in "${a[@]}"; do echo "$i"; done — PesaThe
– PesaThe, Commented Jul 28, 2018 at 8:12
@PesaThe I am running a command and the sending the output to A variable. A=(curl -s 'localhost:9200/something) . the output of this command print strings line by line. how I can send the output to array? — hamid bayat
– hamid bayat, Commented Jul 28, 2018 at 8:22

CS Pei · Accepted Answer · 2018-07-28 11:15:04Z

1

As suggested by @PresaThe,

while read line ; do  echo "$line" ; echo testsss; done <  <(curl -s 'localhost:9200/something)

answered Jul 28, 2018 at 11:15

CS Pei

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1 Comment

Charles Duffy Over a year ago

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