JSON.parse returns object object

Question

I am trying to get the values of item, but when I print the values in the console it displays object instead of the values. How can I access the values?

Here is my code:

var options2;
request.post(opts,function(error,response,body){
    if (!error && response.statusCode == 200 || response.statusCode == 201) {
        var jsonResponse = JSON.parse(body);
        console.log("JSON IS =" + jsonResponse.rows);
        options2 = jsonResponse.rows.reduce((acc, obj) => acc.concat(obj['Item']), []);
    }else{
        console.log(body)
    }
});

What do I miss?

@Hardik BODY IS ={ "columns" : [ "Items" ], "rows" : [ { "Item" : "ABC" }, { "Item" : "DEF" } ] — Sydnie
– Sydnie, Commented Jul 23, 2018 at 6:12
response ({ "columns" : [ "Items" ], "rows" : [ { "Item" : "ABC" }, { "Item" : "DEF" } ]) looks like a object you don't have to parse it again. — Hardik
– Hardik, Commented Jul 23, 2018 at 6:24

ishan shah · Accepted Answer · 2019-09-25 07:42:29Z

3

Print in a new line like:

console.log("JSON IS =");
console.log(jsonResponse.rows);

Or replace '+' with a ',' like this,

console.log("JSON IS = ", jsonResponse.rows);

edited Sep 25, 2019 at 7:42

answered Jul 23, 2018 at 6:16

ishan shah

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1 Comment

Hardik Over a year ago

or you can add comma as a seperator in console.log. console.log("JSON IS =", jsonResponse.rows);

Pavel Vasiluk · Accepted Answer · 2018-07-23 06:24:50Z

0

If the main idea is just to debug object data (doing console logging), you may want to use json.stringify method. https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify That will give you string representation of an object.

answered Jul 23, 2018 at 6:24

Pavel Vasiluk

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2 Comments

Syed Ali Taqi Over a year ago

that will not display the actual object rather a simple string which is very difficult to read/debug.

Syed Ali Taqi Over a year ago

he's using + with string and object that is the problem. he needs two console.log statements or separate current one with , instead of +

Hardik · Accepted Answer · 2018-07-23 06:49:55Z

0

var options2;
request.post(opts,function(error,response,body){
    if (!error && response.statusCode == 200 || response.statusCode == 201) {
        var jsonResponse = JSON.parse(body);
        // **wrap rows in JSON.stringify()**
        console.log("JSON IS =" + JSON.stringify(jsonResponse.rows));
        options2 = jsonResponse.rows.reduce((acc, obj) => acc.concat(obj['Item']), []);
    }else{
        console.log(body)
    }
});

answered Jul 23, 2018 at 6:49

Hardik

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