Accessing array values Javascript

Question

I have gotten the answer I needed for my initial question but now I have another issue with the same array, I am using the getItem and setItem method to only display the iziToast popup once and after it has displayed once not display again (as I have the following array in a function that is within a setInterval function that runs every 30 seconds so essentially every 30 seconds the iziToast popup keeps popping up which I don't want it to do).

Here is the array:

var alerted = localStorage.getItem('alerted') || '';

for(var i in result) {

                console.log(result[i].id);

                        if (alerted != result[i].id) {
                            $('#chatAudio')[0].play();

                            iziToast.show({
                                message: result[i].notification_text,
                                messageColor: '#424242',
                                backgroundColor: '#fff',
                                theme: 'light',
                                animateInside: true,
                                layout: 1,
                                close: false,
                                position: 'bottomLeft',
                                timeout: 5000,
                                progressBar: false
                            });

                            localStorage.setItem('alerted', result[i].id);
                        }
                }

I have edited my question, please take a look at the new question. Thanks — Matt H
– Matt H, Commented Jul 13, 2018 at 21:39
You should ask another question and post your full code (including how you are calling setIntervals, etc...). — fsl
– fsl, Commented Jul 13, 2018 at 21:45

fsl · Accepted Answer · 2018-07-13 19:55:41Z

2

Can't you loop only through the desired range?

var startIndex = 4 // 5th element

for(var i=startIndex; i < results.length; i++) {
    // (...)
}

answered Jul 13, 2018 at 19:55

fsl

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1 Comment

Matt H Over a year ago

I have edited my question, please take a look at the new question. Thanks

Matt H · Accepted Answer · 2018-07-13 20:03:42Z

Someone posted an answer a few minutes ago and it was correct and it worked but for some reason it was deleted so I'm reposting it for anyone who may have missed it.

Here it is:

for(var i in result) {
                if (i < 5) continue;

                console.log(result[i].id);

                        if (alerted != result[i].id) {
                            $('#chatAudio')[0].play();

                            iziToast.show({
                                message: result[i].notification_text,
                                messageColor: '#424242',
                                backgroundColor: '#fff',
                                theme: 'light',
                                animateInside: true,
                                layout: 1,
                                close: false,
                                position: 'bottomLeft',
                                timeout: 5000,
                                progressBar: false
                            });

                            localStorage.setItem('alerted', result[i].id);
                        }
                }

Chrioyles · Accepted Answer · 2018-07-13 20:26:56Z

1

MDN(https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/for...in) says:

Note: for...in should not be used to iterate over an Array where the index order is important.

It seems like in your case order IS important.

Still you could check in which iteration you are by:

result.indexOf(i)

so you can continue while your iteration index is < 4 like this:

if(result.indexOf(i) < 4) continue;

edited Jul 13, 2018 at 20:26

answered Jul 13, 2018 at 20:14

Chrioyles

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1 Comment

Matt H Over a year ago

I have edited my question, please take a look at the new question. Thanks

Geuis · Accepted Answer · 2018-07-13 19:55:38Z

0

for (let i = 4; i < result.length; i++) {
  console.log(result[i]);
}

answered Jul 13, 2018 at 19:55

Geuis

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1 Comment

Matt H Over a year ago

I have edited my question, please take a look at the new question. Thanks

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