Python String Accessing

Question

I am helping a friend with Python and I might be getting confused with C++. So I am curious as to why this would not work. The expected function of this is a Pig Latin translator so if there is a vowel as the first letter 'ay' is added to the end but if the first letter is a consonant, that letter is added to the end and then the 'ay' is added. Example: apple --> appleay watch --> atchway Sorry I completely forgot to post the code (edit)

vowel = ['a','e','i','o','u']
counter = -1
while True: 
    text = input("Write a word to translate. If you do not want to play anymore, 
write exit: ")
if text == "exit":
    break  

elif text[0].lower() in vowel:
    text = text + 'ay'
    print(text)

elif text[0].lower() not in vowel:
    letter = text[0]
    length = len(text) - 1
    for i in range(1, length):
        text[i-1] = text[i]
    text[length + 1] = letter
    print(text)

Where is the function?

Marcus.Aurelianus
– Marcus.Aurelianus

2018-07-12 01:37:16 +00:00
Commented Jul 12, 2018 at 1:37 — Marcus.Aurelianus
– Marcus.Aurelianus, Commented Jul 12, 2018 at 1:37
Could you post the code you have so far?

Ben Jones
– Ben Jones

2018-07-12 01:39:06 +00:00
Commented Jul 12, 2018 at 1:39 — Ben Jones
– Ben Jones, Commented Jul 12, 2018 at 1:39
So the consonant is removed from the first letter as well?

blhsing
– blhsing

2018-07-12 01:41:33 +00:00
Commented Jul 12, 2018 at 1:41 — blhsing
– blhsing, Commented Jul 12, 2018 at 1:41
Sorry, forgot to add the code.

Ryan Marvin
– Ryan Marvin

2018-07-12 01:42:20 +00:00
Commented Jul 12, 2018 at 1:42 — Ryan Marvin
– Ryan Marvin, Commented Jul 12, 2018 at 1:42

blhsing · Accepted Answer · 2018-07-12 01:49:35Z

1

Strings are immutable, so you can't assign to a string at specific index like text[i-1] = text[i].

Instead, use text = text[1:] + text[0] + 'ay' to do what you want:

vowel = ['a','e','i','o','u']
counter = -1
while True:
    text = input("Write a word to translate. If you do not want to play anymore, write exit: ")
    if text == "exit":
        break

    elif text[0].lower() in vowel:
        text = text + 'ay'
        print(text)

    elif text[0].lower() not in vowel:
        text = text[1:] + text[0] + 'ay'
        print(text)

answered Jul 12, 2018 at 1:49

blhsing

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3 Comments

Marcus.Aurelianus Over a year ago

You can just use else for text[0].lower() not in vowel , I think.

Ryan Marvin Over a year ago

I know that that is an option but is there a way for me to individually access the indices of the string and reassign the value like how I tried to do in my original code?

blhsing Over a year ago

@RyanMarvin If you want to do it in your original way, you can cast the string to a list first (like letters = str(text)) so that you can assign values to it at specific indexes, and then convert the list back with join (like ''.join(letters)).

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