fill an array with variables with a loop

Question

I have converted a log file to an array, some elements in array contain the keyword Messages. I want a new array that only contains elements with that keyword.

I tried the following:

$Logfile_array = Get-Content "C:\temp\logfiles\complete_log.txt"
foreach ($array_element in $Logfile_array)
{
    if ($array_element -match 'Messages')
    {
        foreach ($array_element in $Logfile_array)
        {
          $i++
          echo $i
          $array_message[$i] = $array_element
        }
    }
}

So you add the first message once, the second twice and so on. Is that what you intended? — Palle Due
– Palle Due, Commented Jul 4, 2018 at 10:06
What is $array_element supposed to be in the inner loop, when you also use it in the outer loop? — Palle Due
– Palle Due, Commented Jul 4, 2018 at 10:09

henrycarteruk · Accepted Answer · 2018-07-04 10:24:39Z

1

Instead of using foreach to loop through the array and then checking each item, you can use Where-Object to do this for you:

$Logfile_array = Get-Content "C:\temp\logfiles\complete_log.txt"
$array_message = $Logfile_array | Where-Object { $_ -match 'Messages' }

or a one liner:

$array_message = Get-Content "C:\temp\logfiles\complete_log.txt" | Where-Object { $_ -match 'Messages' }

answered Jul 4, 2018 at 10:24

henrycarteruk

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