How to initialize 2D array of string in c++

Question

I am trying to initialized 2D array of string in c++.

std::string A = new std::string [m+1][n+1]

But this is giving me error as array size in new-expression must be constant.

This is C++, use vectors std::vector<std::vector<std::string>> A(...). — Qubit
– Qubit, Commented Jun 29, 2018 at 8:56
In c++ you should use std::vector or std::array instead of those new any_type[m][n] — t.niese
– t.niese, Commented Jun 29, 2018 at 8:56
Possible duplicate of Initializing a two dimensional array of strings, How can i declare and init two dimensional array of strings, etc. — jww
– jww, Commented Jun 29, 2018 at 9:00

Bayleef · Accepted Answer · 2018-06-29 14:42:37Z

0

You could do it the C-Style String way...

char ** array = new char*[10];
for (int i = 0; i < 10; ++i) 
{
     array[i] = new char[100];
}

Then you just delete it in the opposite order you created it when done.

Using the STL is probably a good choice if you need to be safe and modern.

answered Jun 29, 2018 at 14:42

Bayleef

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