Specific data in array from object

Question

I have data like,

const data = {
    pizza: ['Pizza Margherita', 'peppy paneer'],
    sandwich: [],
    burger: ['Veg Maharaja'],
    number: [0,2]
};

I want to store data in the form of an array,

[ 'Pizza Margherita', 'peppy paneer','Veg Maharaja' ]

This is what I tried,

const food = [];
for(key in data) {
    if (data.hasOwnProperty(key)) {
        const element = data[key];
        element.forEach(el => {
            food.push(el)
        });
    }
}
//It Gives output like [ 'Pizza Margherita', 'peppy paneer', 'Veg Maharaja', 0, 2 ]

but I want to ignore last key number.

how do you know if it's an array of the variables you want to keep ? — Muhammad Usman
– Muhammad Usman, Commented Jun 19, 2018 at 11:29
but I want to ignore last key number So the object's structure is uncertain? Or do you just want to add strings only? — CertainPerformance
– CertainPerformance, Commented Jun 19, 2018 at 11:29

Eddie · Accepted Answer · 2018-06-19 11:30:32Z

6

You can convert the object into an array by using Object.values You can flatten the array by using concat and spread syntax. Use filter to get only the string.

const data = {
  pizza: ['Pizza Margherita', 'peppy paneer'],
  sandwich: [],
  burger: ['Veg Maharaja'],
  number: [0, 2]
};

const result = [].concat(...Object.values(data)).filter(isNaN);
console.log(result);

answered Jun 19, 2018 at 11:30

Eddie

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Comments

Muhammad Usman · Accepted Answer · 2018-06-19 11:31:44Z

1

Or you can simply exclude that key named as number

const data = {
    pizza: ['Pizza Margherita', 'peppy paneer'],
    sandwich: [],
    burger: ['Veg Maharaja'],
    number: [0,2]
};

const food = [];
for(key in data) {
    if (data.hasOwnProperty(key) && key!='number') {
        const element = data[key];
        element.forEach(el => {
            food.push(el)
        });
    }
}

console.log(food)

answered Jun 19, 2018 at 11:31

Muhammad Usman

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Comments

zabusa · Accepted Answer · 2018-06-19 11:32:37Z

0

you need to put a condition to avoid iteration over the number key values.

const data = {
    pizza: ['Pizza Margherita', 'peppy paneer'],
    sandwich: [],
    burger: ['Veg Maharaja'],
    number: [0,2]
};

const food = [];
for(key in data) {
    if (data.hasOwnProperty(key)) {
        const element = data[key];
        if(key !== 'number'){
        element.forEach(el => {
            food.push(el)
        });
        }
        
    }
}

console.log(food)

edited Jun 19, 2018 at 11:32

answered Jun 19, 2018 at 11:31

zabusa

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1 Comment

Luca Kiebel Over a year ago

Please explain what your code does in order to solve the problem.

Akhil Aravind · Accepted Answer · 2018-06-19 11:33:52Z

0

This is an old fashioned way, but the result is what you expected.

var data = {
    pizza: ['Pizza Margherita', 'peppy paneer'],
    sandwich: [],
    burger: ['Veg Maharaja'],
    number: [0,2]
};

var food = [];
for(key in data) {
    if (data.hasOwnProperty(key)) {
        const element = data[key];
        element.forEach(el => {
            if(typeof el=='string') food.push(el)
        });
    }
}

console.log(food)

answered Jun 19, 2018 at 11:33

Akhil Aravind

6,0451 gold badge18 silver badges37 bronze badges

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