Python input is not working properly when used within an if statement

Question

I made a quick budgeting program to determine how long it would take to buy something, and I ran into a problem. Whenever I try and run it, the one-time sales items don't get added to the balance. My code is as follows:

graphicsCard = 50
amdCpu = 80
itelCpu = 99
ram = 140
guitar = 199
case = 99
balance = 21
if (input('Has the graphics card been sold yet?').lower == "yes"):
    balance += graphicsCard
if (input('Has the AMD cpu been sold yet?').lower == "yes"):
    balance += amdCpu
if (input('Has the intel CPU been sold yet?').lower == "yes"):
    balance += intelCpu
if (input('Has the RAM been sold yet?').lower == "yes"):
    balance += ram
if (input('Has the Guitar been sold yet?').lower == "yes"):
    balance += guitar
if (input('Has the Case been sold yet?').lower == "yes"):
    balance += case

I added an else statement to after the first if, to detect if it was reading my 'yes' answer properly, and it was not.

You've forgotten to call the lower method, with (). So, instead of testing whether the result of calling lower() on the input string matches "yes", you're testing whether the lower method itself matches "yes". Which of course it doesn't. — abarnert
– abarnert, Commented Jun 17, 2018 at 20:25

Daniel Roseman · Accepted Answer · 2018-06-17 20:25:43Z

2

lower is a method, you need to call it:

if input('Has the graphics card been sold yet?').lower() == "yes":

Note, as I show you don't need parentheses around the condition itself.

edited Jun 17, 2018 at 20:25

answered Jun 17, 2018 at 20:25

Daniel Roseman

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Joana Pascoal · Accepted Answer · 2018-06-17 20:31:22Z

1

You should try .lower()

>>> myinput = input('Enter something: ')
Enter something: yes
>>> myinput.lower
<built-in method lower of str object at 0x7f79b2391068>
>>> myinput.lower()
'yes'

answered Jun 17, 2018 at 20:31

Joana Pascoal

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